http://prntscr.com/lm3sa0
@Vocaloid
|dw:1542989256746:dw|
hmm, im thinking D
good
then for b) |dw:1542989403905:dw|
for a fractional exponent, remember the numerator becomes the power and the denominator becomes the root
A is one
good and if a is greater than b, then a/b must be greater than 1 so if 3 is raised to an exponent greater than 1, is the end result greater or less than 3?
greater
good so first two choices
check question 10 the 1/3 exponent applies to the 8 as well
I actually had trouble with that
what is 8^(1/3) = ?
2
good so the coefficient in front should be 2 not 8
so B?
yes
check question 3 again -4sqrt(2x^3y) can only simplify to -4xsqrt(2xy). the 2 has to stay within the radical because it can't be simplified further
that being said you can factor the expression from B into one of the other answer choices
take 2x^3 * sqrt(2xy) - 4x*sqrt(2xy) and factor out sqrt(2xy).
A*B - A*C = A(B-C) factors out A apply this logic to 2x^3 * sqrt(2xy) - 4x*sqrt(2xy) and factor out sqrt(2xy).
confused LOL
if you see something like "A*B - A*C" where both terms have some factor A in common, you can remove A from both expressions, and write it outside the parentheses to get A(B-C)
notice that both terms in 2x^3 * sqrt(2xy) - 4x*sqrt(2xy) have sqrt(2xy), so you can remove this from both expressions, write it outside the parentheses and get...?
1. identify the common factor sqrt(2xy) from 2x^3y * sqrt(2xy) - 4x*sqrt(2xy) 2. remove the factor sqrt(2xy) from both expressions to get 2x^3y - 4x 3. put the expression inside parentheses and write the common factor outside sqrt(2xy) ( 2x^3y - 4x )
would recommend reviewing how to factor out a GCF
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