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Mathematics 18 Online
itzsummer:

Mr.Lopez wants to cover the walls of his unfinished basement with pieces of plasterboard that are 8 feet high, 4 feet wide, and 1/4 inch thick. If the basement measure 24 feet wide, 16 feet long, and 8 feet tall, how many pieces of plasterboard will he need to cover all four walls?

Shadow:

You simply need to calculate the surface area of the walls then divide that by the surface area of one tile. That will give you the total # of tiles needed for this project. Do you know how to solve for surface area?

itzsummer:

lol im soo confused

itzsummer:

like theirs so many numbers which numbers do i divide and how

itzsummer:

please help me, please

Shadow:

Lets start with the shape of this room. It is 24 ft wide and 16 ft long, and 8 ft tall. |dw:1543819400071:dw| We need to cover all the walls.

itzsummer:

8 times 24 times 16?

Shadow:

So first we need to figure out how much area we need to cover. \[A = length \times height\] \[A_{24} = 24 \times 8 \times 2 = 384 ft^2\] This means that there are two sides that are 24 ft long and 8 ft tall, and gives us the area of these two sides. Next, we have the sides that are 16 ft long \[A_{16} = 16 \times 8 \times 2 = 256 ft ^2\] There are two sides that are 16 ft long and 8 ft tall.

Shadow:

Add those two numbers together, and we get 640 ft^2 That is the total area of the walls of this basement.

Shadow:

Does that make sense to you so far?

Hero:

|dw:1543819718896:dw| Since each piece of plaster is 4ft wide and 8ft long it'll take 6 pieces to cover one 24ft wide wall.

Hero:

8 ft high rather*

itzsummer:

huh

itzsummer:

is their a formula

Shadow:

@Hero Any idea why they gave us the thickness?

Hero:

If that went over your head, just ignore it

Hero:

so that the plaster can fit into the wall.

itzsummer:

so did shadow get it right?

Shadow:

Ah I see what you were doing Hero. My method is a bit more brute force lol.

itzsummer:

ummm hows ur method

Shadow:

Just solving for the total area I need to cover, then dividing it by the area of one tile, as that would give the total # of tiles needed to cover that area.

Shadow:

Hero's way is more quick, but requires you to think about it a different way. There's no formula.

Hero:

|dw:1543820173045:dw| You can fit pieces 7 - 10 on the side adjacent to the front wall.

Shadow:

Do you see what Hero did? Since each til is 4 feet wide, he simply did 24/4 = 6.

Shadow:

Because the tile is the same height as the wall, we only need to consider the width.

itzsummer:

so the answer is 6

Shadow:

Ah, no.

Shadow:

Six tiles covers one side that is 24 feet wide.

itzsummer:

lol this is so hard

Hero:

Well there's at least 10 pieces of plaster on two walls but yet the other two walls still need to be covered. #Hint

itzsummer:

so the answer is 20

Hero:

Good guess

itzsummer:

so that was the answer

itzsummer:

thanks sooooo much

Hero:

You're welcome. Thanks for the assist @Shadow. I was too lazy to draw a picture.

itzsummer:

lol yall are the best thanks so much

Shadow:

Yeah I wasn't happy about drawing it either, but it's the best way to envision the problem, lol.

itzsummer:

ummm it was helpful though thanks lol

itzsummer:

yall are soo lazy lol

itzsummer:

😂

Shadow:

Glad we could help (:

Hero:

We're just lazy enough to help you

itzsummer:

yup thank god yall are here

Shadow:

Well put Hero

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