Mr.Lopez wants to cover the walls of his unfinished basement with pieces of plasterboard that are 8 feet high, 4 feet wide, and 1/4 inch thick. If the basement measure 24 feet wide, 16 feet long, and 8 feet tall, how many pieces of plasterboard will he need to cover all four walls?
You simply need to calculate the surface area of the walls then divide that by the surface area of one tile. That will give you the total # of tiles needed for this project. Do you know how to solve for surface area?
lol im soo confused
like theirs so many numbers which numbers do i divide and how
please help me, please
Lets start with the shape of this room. It is 24 ft wide and 16 ft long, and 8 ft tall. |dw:1543819400071:dw| We need to cover all the walls.
8 times 24 times 16?
So first we need to figure out how much area we need to cover. \[A = length \times height\] \[A_{24} = 24 \times 8 \times 2 = 384 ft^2\] This means that there are two sides that are 24 ft long and 8 ft tall, and gives us the area of these two sides. Next, we have the sides that are 16 ft long \[A_{16} = 16 \times 8 \times 2 = 256 ft ^2\] There are two sides that are 16 ft long and 8 ft tall.
Add those two numbers together, and we get 640 ft^2 That is the total area of the walls of this basement.
Does that make sense to you so far?
|dw:1543819718896:dw| Since each piece of plaster is 4ft wide and 8ft long it'll take 6 pieces to cover one 24ft wide wall.
8 ft high rather*
huh
is their a formula
@Hero Any idea why they gave us the thickness?
If that went over your head, just ignore it
so that the plaster can fit into the wall.
so did shadow get it right?
Ah I see what you were doing Hero. My method is a bit more brute force lol.
ummm hows ur method
Just solving for the total area I need to cover, then dividing it by the area of one tile, as that would give the total # of tiles needed to cover that area.
Hero's way is more quick, but requires you to think about it a different way. There's no formula.
|dw:1543820173045:dw| You can fit pieces 7 - 10 on the side adjacent to the front wall.
Do you see what Hero did? Since each til is 4 feet wide, he simply did 24/4 = 6.
Because the tile is the same height as the wall, we only need to consider the width.
so the answer is 6
Ah, no.
Six tiles covers one side that is 24 feet wide.
lol this is so hard
Well there's at least 10 pieces of plaster on two walls but yet the other two walls still need to be covered. #Hint
so the answer is 20
Good guess
so that was the answer
thanks sooooo much
You're welcome. Thanks for the assist @Shadow. I was too lazy to draw a picture.
lol yall are the best thanks so much
Yeah I wasn't happy about drawing it either, but it's the best way to envision the problem, lol.
ummm it was helpful though thanks lol
yall are soo lazy lol
😂
Glad we could help (:
We're just lazy enough to help you
yup thank god yall are here
Well put Hero
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