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Mathematics 7 Online
CC12:

Math help please

CC12:

1 attachment
CC12:

@dude

CC12:

82?

dude:

Uh I am assuming \\(\angle 3\) is this part 1545000988-5c16d81c1317c963f4fa9600-image.png That is not greater than 90ยบ

CC12:

yes

CC12:

Im confused on it

dude:

|dw:1545001590030:dw|

dude:

Do you know what the sum of angles 1 and 2 are?

CC12:

yes 98

dude:

Since it states that s \(\bf bisects\) the lines, it is spilt into 2 equal angled sides

CC12:

49

CC12:

@dude

CC12:

@Vocaloid can you please help im confused

Hero:

@CC12 if \(m \parallel n\), what what kind of line is \(t\)?

CC12:

i dont know

Hero:

Ever heard of a transversal?

CC12:

yes

Hero:

That's what \(t\) is; a transversal. Do you remember the kinds of angles that are created as a result of a transversal intercepting two parallel lines?

Hero:

Are you ready to continue @CC12

CC12:

yes

Hero:

Okay, so basically the transversal \(t\) creates corresponding angles here: |dw:1545014746170:dw|

Hero:

Angle \(m\) corresponds to angle \(DEF\) Your diagram makes it difficult to describe angle \(n\) but it includes angle \(3\). Do you understand this?

Hero:

angles \(m\) and \(n\) are corresponding angles.

Hero:

Likewise for the angles depicted in the diagram. I hope you're not too confused, but I'll help you out since the problem was setup to confuse you

CC12:

yes i sorta understand

Hero:

|dw:1545014961189:dw| Let's say \(\angle m = \angle 1 + \angle 2\) and \(n = \angle 3 + \angle 5\)

CC12:

ok

Hero:

\(m = n\) In other words \(\angle 1 + \angle 2 = \angle 3 + \angle 5\)

Hero:

Oops. I didn't see that they already included an angle 5. smh

Hero:

Now I have to change everything to angle six.

Hero:

|dw:1545015185831:dw|

Hero:

\(\angle 1 + \angle 2 = \angle 3 + \angle 6\) We already know the measure of \(\angle 1\) and \(\angle 2\)

Hero:

I should also mention that after reviewing you should be familiar with alternate exterior angles.

CC12:

find angle 3 and 6 now or

Hero:

Alternate Exterior Angles are also congruent

Hero:

In other words \(\angle1 + \angle 2 = \angle 4 + \angle 5 \)

Hero:

This is where it gets complicated, because we have to make sure we distinguish which angles are congruent to which

Hero:

I'll explain later, but basically \(\angle 1\) corresponds to \(\angle 5\) and \(\angle 2\) corresponds to \(\angle 4\)

Hero:

If you were familiar with vertical angles, then you'd also know that \(\angle 4 \cong \angle 3\)

Hero:

So in essence, \(\angle 2 \cong \angle 4 \cong \angle 3\)

CC12:

sorry i was writing the problem out and i got angle 3 =49 degrees

Hero:

How did you get that? Show your work please

Hero:

If I'm being completely honest though, there is no way to actually prove those angles are truly congruent.

CC12:

you add angle 1 and angle 2 which is 98 angle 4 is 98/2= 49 degrees

Hero:

Yeah, that's probably right. I should never have taken a nap. That was my reasoning the first time.

Hero:

I forgot my own reasoning, but I suspect @dude helped you with this.

CC12:

you get 49 degrees because angle 3 and 4 are vertical angles

CC12:

i think thats right

Hero:

You don't even need vertical angles for it.

dude:

Yeah haha Take a nap, we need a good nights rest ;p

CC12:

oh you dont

Hero:

Nope, you don't. You just need to know that \(\angle 1\) and \(\angle 2\) corresponds to the blank angle plus angle 3

Hero:

Since \(s\) bisects the blank angle and angle 3 are congruent

CC12:

oh ok

Hero:

\(\angle 1 + \angle 2 = 98\) and \(\angle b + \angle 3 = 98\) as well. But \(\angle b = \angle 3\) so you can just divide by \(2\) to get the result

Hero:

Anyways, I've confused you enough.

CC12:

Thank you so so much for explaing it to me

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