Math help please
@dude
82?
Uh I am assuming \\(\angle 3\) is this part
That is not greater than 90ยบ
yes
Im confused on it
|dw:1545001590030:dw|
Do you know what the sum of angles 1 and 2 are?
yes 98
Since it states that s \(\bf bisects\) the lines, it is spilt into 2 equal angled sides
49
@dude
@Vocaloid can you please help im confused
@CC12 if \(m \parallel n\), what what kind of line is \(t\)?
i dont know
Ever heard of a transversal?
yes
That's what \(t\) is; a transversal. Do you remember the kinds of angles that are created as a result of a transversal intercepting two parallel lines?
Are you ready to continue @CC12
yes
Okay, so basically the transversal \(t\) creates corresponding angles here: |dw:1545014746170:dw|
Angle \(m\) corresponds to angle \(DEF\) Your diagram makes it difficult to describe angle \(n\) but it includes angle \(3\). Do you understand this?
angles \(m\) and \(n\) are corresponding angles.
Likewise for the angles depicted in the diagram. I hope you're not too confused, but I'll help you out since the problem was setup to confuse you
yes i sorta understand
|dw:1545014961189:dw| Let's say \(\angle m = \angle 1 + \angle 2\) and \(n = \angle 3 + \angle 5\)
ok
\(m = n\) In other words \(\angle 1 + \angle 2 = \angle 3 + \angle 5\)
Oops. I didn't see that they already included an angle 5. smh
Now I have to change everything to angle six.
|dw:1545015185831:dw|
\(\angle 1 + \angle 2 = \angle 3 + \angle 6\) We already know the measure of \(\angle 1\) and \(\angle 2\)
I should also mention that after reviewing you should be familiar with alternate exterior angles.
find angle 3 and 6 now or
Alternate Exterior Angles are also congruent
In other words \(\angle1 + \angle 2 = \angle 4 + \angle 5 \)
This is where it gets complicated, because we have to make sure we distinguish which angles are congruent to which
I'll explain later, but basically \(\angle 1\) corresponds to \(\angle 5\) and \(\angle 2\) corresponds to \(\angle 4\)
If you were familiar with vertical angles, then you'd also know that \(\angle 4 \cong \angle 3\)
So in essence, \(\angle 2 \cong \angle 4 \cong \angle 3\)
sorry i was writing the problem out and i got angle 3 =49 degrees
How did you get that? Show your work please
If I'm being completely honest though, there is no way to actually prove those angles are truly congruent.
you add angle 1 and angle 2 which is 98 angle 4 is 98/2= 49 degrees
Yeah, that's probably right. I should never have taken a nap. That was my reasoning the first time.
I forgot my own reasoning, but I suspect @dude helped you with this.
you get 49 degrees because angle 3 and 4 are vertical angles
i think thats right
You don't even need vertical angles for it.
Yeah haha Take a nap, we need a good nights rest ;p
oh you dont
Nope, you don't. You just need to know that \(\angle 1\) and \(\angle 2\) corresponds to the blank angle plus angle 3
Since \(s\) bisects the blank angle and angle 3 are congruent
oh ok
\(\angle 1 + \angle 2 = 98\) and \(\angle b + \angle 3 = 98\) as well. But \(\angle b = \angle 3\) so you can just divide by \(2\) to get the result
Anyways, I've confused you enough.
Thank you so so much for explaing it to me
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