Which of the following statements have the same result? Explain each step in solving each one. f(3) when f(x) = 2x + 2 f−1(4) when f(x) = 3x minus 4, all over 5 y + 10 = 2y + 1
f(3) when f(x) = 2x + 2 f−1(4) when f(x) = 3x minus 4, all over 5 You should probably solve them to have an idea xD
Do you know what this `f(3) when f(x) = 2x + 2` refers to?
sorry ive been solving it by my self i think i got this but would you check my answers? this is what i have so far
Okay sure
alright this is my over all answer
I. find f(3) we are going to replace x with 3 so it would look like this f(3)=2(3)+2 once we have this we multiply 2*3 which equals 6 and we plug that in. (3) = 6 + 2 then we add 6+2 which equals 8 which is our answer f(3) = 8 II.find f^-1(4) we are going to replace f(x) with y once we have this we are going y = (3x - 4)/5 to take our equation and swap the variables putting x on the outside x = (3y - 4)/5 and y on the inside next we have to solve for y. which equals 5x = 3y - 4 next we swap sides and place 5x -4 on the left side of the = sign then 5x + 4 = 3y turn the - into a + turn it into a fraction by placing (5x+4) over 3 (5x + 4) over 3 = y f^-1(x) = (5x + 4) over 3 Once you have (5x+4) over 3 we are going to take f^-1(x) f(4) = (5(4) + 4)/3 and replace it with f(4) we then add 4 on both sides and solve f(4) = (20 + 4)/3 this equals 5*4=20 then 20+4=24 which makes the fraction 24/3 f(4) = 24/3 we then divide 24 by 3 which equals 8 f(4) = 8 III. y + 10 = 2y + 13 we are going to start by subtracting 10 from both sides y+10-10=2y+1-10 then we simplify y=2y-9 we then subtract 2y from both sides y-2y=2y-9-2y we then simplify again -y=-9 then we divide by -1 -y -9
=
-1 -1 we simplify one more time and we get our answer 9 this means I and II have the same result of 8.
You don't have to swap the sides mid step but if it helps then yes Looks good though
Thank you dude im actually proud of my self with how this turned out you guys are alot of help here :D
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