Question

Need some explanation >.<

Answer 1

Find the form for \(y_p\) to
\(y''+2y'-3y=f(x)\)
where f(x) equals
b) \(2xe^xsinx\)

Answer 2

\(m_2+2m-3=0\)

\((m-1)(m+3)=0\)

\(m=1,m=-3\)

\(y_h(x)=Ae^x+Be^{-3x}\)

Answer 3

http://prntscr.com/m5d6kw

Answer 4

how do u get \(y_p=(C_1x+C_0)e^xcos~x+(B_1x+B_0)e^xsin~x\) ?

Answer 5

@nuts whenever u r free,can u help me check this out? >.<
Thanks ;)

Answer 6

Trial & error.

Unless you understand the differential as a linear operator.

Answer 7

yeah,it is using Method of Undetermined Coefficient
I think I got it
My notes need to be edit >.<

Thanks 4 the help!

Answer 8

\[\rm When ~f(x)=C_0x+C_1 \rightarrow y_p=\color{blue}{A}x+\color{red}{B}\]\[\rm When ~f(x)=e^x \rightarrow y_p=\color{blue}{A}e^x\]\[\rm When ~f(x)=sin(x) \rightarrow y_p=\color{blue}{A}cos(x)+\color{red}{B}sin(x)\]
\[\rm f(x)=2xe^xsinx \]\[y_p=(Ax+B)e^xcosx+(Cx+D)e^xsinx\]

Answer 9

I think using a different letter is better than using the subscript for coefficients

Answer 10

hmm the images up there are from your notes ?? :o
looks very complicated/confusing (at least for me...)

Answer 11

http://prntscr.com/m5d6kw ---->there are some error in this notes,smh

Answer 12

https://assets.questioncove.com/attachments/1547183180-5c3742f0593fbf85c032e000-image.png
This one is better

Answer 13

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Nnesha
I think using a different letter is better than using the subscript for coefficients
\(\color{#0cbb34}{\text{End of Quote}}\)
Haha,truee

Answer 14

still confusing :d
so many terms....