Question

http://prntscr.com/mc7m0f

Answer 1

@Vocaloid

Answer 2

they already tell you that "y = x + 3"

so, since y = x + 3, you can take the first equation, 2x + y = 3, replace "y" with "x+3", then solve for x

after you have x, you can just pick one of the equations, plug in x, solve for y

Answer 3

So x equals 0 .

then y=0+3?

Answer 4

good

so x = 0, y = 3

(0,3)

Answer 5

got it

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Answer 6

start with "sum of two numbers is 66"

so x + y = 66

"the larger number is 2 more than three times the smaller number"
so x = 3y + 2

so you can plug x back into the first equation, solve for x

Answer 7

where do i plug in x?

Answer 8

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Vocaloid
so you can plug x ***back into the first equation***, solve for x
\(\color{#0cbb34}{\text{End of Quote}}\)

Answer 9

Confusedd loll

Answer 10

you are given

x = 3y + 2

this tells you that x = 3y + 2

so you can take this thing for x, replace "x" in the first equation with "3y + 2" and solve for y.

Answer 11

Wouldnt that be a fraction

Answer 12

y=16

Answer 13

so D

Answer 14

good

Answer 15

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Answer 16

notice how you have -2y in one equation and +2y in the other equation, so try adding the equations together. the y's will cancel out and you can then solve for x.

Answer 17

C?

Answer 18

good

Answer 19

http://prntscr.com/mc98ts

Answer 20

@Vocaloid

Answer 21

Nicole try rewriting this text in equations

Answer 22

3x + ...

Answer 23

(3x)+(4y)=81

Answer 24

(2x)-(4y)=-46

Answer 25

I think the answer is A. am I correct?

Answer 26

3x+4y=81
2x-4y=-46

Answer 27

http://prntscr.com/mc9hzv

Answer 28

Am I right?

Answer 29

no - try the intersection point of these two lines

Answer 30

B?

Answer 31

sorry you are right with this marked choice

Answer 32

ohh okay

http://prntscr.com/mc9khx

Answer 33

D?

Answer 34

@Vocaloid @SmokeyBrown @jhonyy9

Answer 35

i m not sure in D

Answer 36

hmm

Answer 37

in case of D give the x=-2 and see what you get

in case of first equation is right but in case of second not is