Question

help @vocaloid

Answer 1

2. work = force*distance
3. average value function formula

Answer 2

so 1*.25=.25
but that's not the answer teacher gave us .125j as the answer

Answer 3

@Vocaloid

Answer 4

ah I see where I went wrong

F = kx for a spring
you are given force = 1N and distance = 0.25m
you can solve for k, then plug everything into the work equation U = (1/2)kx^2

Answer 5

so do I still do force *distance?

Answer 6

F = kx for a spring
you are given force = 1N and distance = 0.25m
you can solve for k, then plug everything into the work equation U = (1/2)kx^2

Answer 7

@Vocaloid

Answer 8

Like I said, plug in distance, solve for k, then solve for work.

Answer 9

distance is x ?

Answer 10

yes

Answer 11

k=4

Answer 12

good, keep going

Answer 13

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Vocaloid
F = kx for a spring
you are given force = 1N and distance = 0.25m
you can solve for k, then plug everything into the work equation U = (1/2)kx^2
\(\color{#0cbb34}{\text{End of Quote}}\)

work = (1/2)kx^2 = ?

Answer 14

kx^2
or x^2

Answer 15

got it .25/2

Answer 16

okay so 3 I have 1/2 integral 1-3 e^x-e^-x dx

Answer 17

@Vocaloid not sure what I do next

Answer 18

evaluate the integral.

Answer 19

so 1/2[e^3-e^-3] dx?

Answer 20

and the name with 1 ?

Answer 21

you need to evaluate the integral, you can't just plug in x = 3

Answer 22

?

Answer 23

calculate what the 1/2 of the integral of e^x - e^(-x) would be, from x = 1 to x = 3.

Answer 24

1+e^6-e^2-e^4/2e^3

Answer 25

good, convert this to decimal form.

Answer 26

8.52

Answer 27

since the pulling force is constant I believe you can just do force*distance

Answer 28

the answer is 1000J so no

Answer 29

our hint @Vocaloid

Answer 30

I don't really understand where they got 100N/20m from, but I suppose you could take the integral of 20xdx from x = 0m to x = 10m

Answer 31

yep !

Answer 32

next question has 5 parts joy

Answer 33

we aren't given answers for these so get whatever we get

Answer 34

they gave us a though

Answer 35

so what do I do for b?

Answer 36

you just need to re-write the functions and the limits of integration in terms of y instead of x

Answer 37

so how would I do that and then solve for the area?

Answer 38

look at the problem
you are given the limits of integration and the functions in terms of x
re-write them in terms of y.

Answer 39

ok so just write an equation

Answer 40

y = x^2
y = x + 2
notice how these equations are solved for y, in terms of x

solve them for x, in terms of y.

Answer 41

and then plug that in to the equation maybe I'm doing something wrong

Answer 42

after you solve for the limits in terms of y, re-write the original integral in terms of y

Answer 43

a=integral 0-2 (

Answer 44

crud hold up didn't mean to post that

Answer 45

what should I have for b and c I have those done

Answer 46

@Vocaloid

Answer 47

@Vocaloid

Answer 48

help @Vocaloid ?

Answer 49

@Ultrilliam @Hero