Question

Probability Questions...
A player gets to throw 4 darts at the target shown. Assuming the player will always hit the target, the probability of hitting an odd number three times is ______ times more than the probability of hitting an even number three times.

Answer 1

there are three odd numbers (1,3,5)
and two even numbers (2,4)
out of 5 total possibilities

the probability of hitting one odd number is therefore 3/5
to get three in a row, we just multiply this by itself three times, so
P(three odd numbers in a row) = (3/5)(3/5)(3/5)

same logic with getting three even numbers in a row
P(three even numbers in a row) = (2/5)(2/5)(2/5)

Answer 2

so you would just figure out how many times more (3/5)^3 is compared to (2/5)^3

Answer 3

2.25

Answer 4

i have another question if youd like to help

Answer 5

hm I think i got something slightly different for (3/5)^3 / (2/5)^3

Answer 6

actually hmmm

Answer 7

since the person gets to throw four darts I think the calculation becomes a bit more complex

Answer 8

it was 2.25 apparently on plato

Answer 9

ah I see

Answer 10

if you have another one I'll take a look

Answer 11

even my teacher is having trouble

Answer 12

this is the last question for me to graduate. unless i get it wrong

Answer 13

hmm I really don't feel confident about this solution, my best guess is <XOB = 2 times <QON, personally I'd try to get a second opinion :/ maybe I can ask someone

Answer 14

please do

Answer 15

sure

Answer 16

it was correct

Answer 17

<QON = 55
so 55 * 2 = <XOB
<XOB Is 110