Question

@dude

Answer 1

First step I will subtract 3y from both sides of the equation.
x = 8-3y

2x-y= 2

Solve the first equation

x = 8 - 3y

2(8-3y)-y=2

Solve the second equation solve for y

x = 8-3y

y = 2

Replace y with 2

x = 8 - 3 * 2

y=2

Simplify x = 8 - 3 * 2

x=2

y=2

(2,2)

Answer 2

x + 3y = 8 2x - y = 2 was the question I solved by substitution

Answer 3

Solve the first equation

x = 8 - 3y

2(8-3y)-y=2

Solve the second equation solve for y

x = 8-3y

y = 2
this part

Answer 4

2(8-3y)-y=2 in this part my teacher asked what did I do with the 2

Answer 5

and I couldn't answer because I didn't know what I did with the 2

Answer 6

@AnimeGhoul8863

Answer 7

Okay your work is a bit confusing, you have 2 different equations and describing steps for 1 but not sure which

Answer 8

this is a system of equations

Answer 9

This is the question
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V
x + 3y = 8

2x - y = 2

Answer 10

First step I will subtract 3y from both sides of the equation.
x = 8-3y

2x-y= 2

Answer 11

first step ^

Answer 12

Second and Third step

Solve the first equation

x = 8 - 3y

2(8-3y)-y=2

Solve the second equation solve for y

x = 8-3y

y = 2

Answer 13

I don't understand this part it says solve the first equation but we solve 2x-y= 2

Answer 14

@dude

Answer 15

Yes I know what systems of equations are. Don't write the second equation if you aren't doing anything to it

Answer 16

lol

Answer 17

I figured out what I did wrong

Answer 18

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Kabbed
Second and Third step

Solve the first equation No, this doesn't imply anything, say substitute

x = 8 - 3y

2(8-3y)-y=2

Solve the second equation solve for y Once you substitute, there is only 1 equation. Not 2.

x = 8-3y

y = 2
\(\color{#0cbb34}{\text{End of Quote}}\)

Answer 19

thank you