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eviant:

Math help pls

7 years ago

eviant:

1 attachment

4.png

7 years ago

eviant:

@Shadow

7 years ago

eviant:

@dude @Vocaloid

7 years ago

jimthompson5910:

First we need to find the length of the altitude, which I'll call y for now see the attached image below

1 attachment

Screenshot_119.png

7 years ago

jimthompson5910:

Because of the fact that the triangles are similar, we can form the proportion $\Large \frac{9}{y} = \frac{y}{3}$ which solves to... $\Large 9*3 = y*y$ $\Large 27 = y^2$ $\Large y^2 = 27$ $\Large \sqrt{y^2} = \sqrt{27}$ $\Large y = \sqrt{27}$

Now we use the pythagorean theorem to solve for x. Focus on the smaller triangle on the right hand side. This triangle has legs of $\Large y = \sqrt{27}$ and $\Large 3$. The hypotenuse is $\Large x$ Let, $\Large a = \sqrt{27}$ $\Large b = 3$ $\Large c = x$ So, $\Large a^2 + b^2 = c^2$ $\Large (\sqrt{27})^2 + 3^2 = x^2$ $\Large 27 + 9 = x^2$ $\Large 36 = x^2$ $\Large x^2 = 36$ $\Large \sqrt{x^2} = \sqrt{36}$ $\Large x = 6$

7 years ago

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