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Mathematics 5 Online

eviant:

Math help pls

7 years ago

eviant:

1 attachment

4.png

7 years ago

eviant:

@Shadow

7 years ago

eviant:

@dude @Vocaloid

7 years ago

jimthompson5910:

First we need to find the length of the altitude, which I'll call y for now see the attached image below

1 attachment

Screenshot_119.png

7 years ago

jimthompson5910:

Because of the fact that the triangles are similar, we can form the proportion \(\Large \frac{9}{y} = \frac{y}{3}\) which solves to... \(\Large 9*3 = y*y\) \(\Large 27 = y^2\) \(\Large y^2 = 27\) \(\Large \sqrt{y^2} = \sqrt{27}\) \(\Large y = \sqrt{27}\)

Now we use the pythagorean theorem to solve for x. Focus on the smaller triangle on the right hand side. This triangle has legs of \(\Large y = \sqrt{27}\) and \(\Large 3\). The hypotenuse is \(\Large x\) Let, \(\Large a = \sqrt{27}\) \(\Large b = 3\) \(\Large c = x\) So, \(\Large a^2 + b^2 = c^2\) \(\Large (\sqrt{27})^2 + 3^2 = x^2\) \(\Large 27 + 9 = x^2\) \(\Large 36 = x^2\) \(\Large x^2 = 36\) \(\Large \sqrt{x^2} = \sqrt{36}\) \(\Large x = 6\)

7 years ago

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