Question

help please

Answer 1

http://prntscr.com/n2qzhb

Answer 2

Hello @Kabbed What is your question? What do you need help with?

Answer 3

Factor 7 out of 7y

Move the negative one from the denominator of y/-1

Answer 4

That screenshot is a list of a lot of different things.

Answer 5

how does that happen a -1 appears out of no where

Answer 6

I see what you mean. This is all quite confusing. Do you have the original expression that you were required to factor

Answer 7

it goes from - 7(y)/-7 to y/-1 how

Answer 8

the question is

x + 3y = 8

2x - y = 2

Answer 9

solve by substitution

Answer 10

\[- \frac{ 7y }{ -7 } \rightarrow \frac{ y }{ -1 }\]
hmm

Answer 11

This looks like an error to me. Any thoughts @dude

Answer 12

Uh from what I get here
1. This is from an online calculator smh
2. This seems to be 2 equations
x=8-3y and -7y=-14

The calculator *cough* just isolated y, there is just a lot of explanation

Answer 13

As for solving by substitution, I'd do:
\[x + 3y = 8 \]
\[2x - y = 2 \]
Taking the first equation, solve for x
\[x = -3y + 8\]
Input this into the second equation
\[2(-3y +8) - y = 2\]
\[-6y + 16 -y = 2\]
\[-7y + 16 = 2\]
\[-7y = -14\]
\[\frac{ -7y }{ -7 } = \frac{ -14 }{ -7}\]
\[y = 2\]

Answer 14

From here you'd just input y = 2 into the first equation then solve for x and you're good.

Answer 15

Does that make sense @Kabbed ?

Answer 16

Ah you're right dude, this is an online calculator, lol

Answer 17

but how do I get x = 2

Answer 18

Input y = 2 into the equation we derived earlier.

\[x = -3y + 8\]
\[x = -3(2) + 8 \rightarrow x = -6 + 8 \rightarrow x = 2\]

Answer 19

how do you solve -7y/-7 = -14/-7

Answer 20

That step is just dividing both -7y and -14 by -7, since -7 is a common factor to both

-7y = -7 times y
-14 = -7 times 2

Answer 21

Division is the inverse operation of multiplication, thus by dividing by this common factor, we get both y and 2 subsequently.

Answer 22

Does that make sense?

Answer 23

no sorry so I just divide -7y by -7 how do I do that what do I get

Answer 24

You get y

Answer 25

how

Answer 26

Any number divided by itself is 1.

Answer 27

oh thanks

Answer 28

-7 divided by -7 = 1

1 times y = y

Answer 29

and what about -14 divided by -7

Answer 30

What about it? You'd just divide.

Answer 31

I get 2

Answer 32

y/2

Answer 33

y/2 turns into y = 2 somehow

Answer 34

2x - y = 2 so were solving for this equation and then we solve for x = -3y+8

Answer 35

\[\frac{ -7y }{ -7} = \frac{ -14 }{ -7 } \rightarrow y = 2\]

Answer 36

You don't get y/2 anywhere

Answer 37

ok

Answer 38

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Shadow
As for solving by substitution, I'd do:
\[x + 3y = 8 \]
\[2x - y = 2 \]
Taking the first equation, solve for x
\[x = -3y + 8\]
what do you do here should I say subtract 3y something

Answer 39

You're isolating x...

Answer 40

is there another way I could call it something more simpler

Answer 41

Well that's exactly what you're doing so no

Answer 42

'Isolate x for the first equation"

Answer 43

how does 3y become -3y

Answer 44

Because you subtract 3y from both sides

Answer 45

I'm sorry but this is basic algebra. What class are you in and are you unfamiliar with all of these concepts, or does this lesson/hw ask for a step by step explanation of how to solve this?

Answer 46

As for solving by substitution, I'd do:
\[x + 3y = 8 \]
\[2x - y = 2 \]
Subtract 3y from both sides
\[x = -3y + 8\]

2(−3y+8)−y=2
\(\color{#0cbb34}{\text{End of Quote}}\)

Answer 47

step by step explanation

Answer 48

Well I've already shown you that with my post earlier. I have to go, so simply refer to that.

Answer 49

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Shadow
As for solving by substitution, I'd do:
\[x + 3y = 8 \]
\[2x - y = 2 \]
Taking the first equation, solve for x
\[x = -3y + 8\]
Input this into the second equation
\[2(-3y +8) - y = 2\]
\[-6y + 16 -y = 2\]
\[-7y + 16 = 2\]
\[-7y = -14\]
\[\frac{ -7y }{ -7 } = \frac{ -14 }{ -7}\]
\[y = 2\]
\(\color{#0cbb34}{\text{End of Quote}}\)

Answer 50

-7y + 16 = 2

-7y = -14

how did that happen @shadow

Answer 51

@Aureo @umm help what did shadow do

-7y + 16 = 2

-7y = -14

how did he do that

Answer 52

@Shadow @dude help me what did you do

-7y + 16 = 2

-7y = -14

how did you get -14

Answer 53

dude help me

Answer 54

-7y + 16 = 2

You want to isolate y

What is the opposite of adding 16?

Answer 55

subtracting

Answer 56

Right

Subtract 16 on both sides


-7y + 16 = 2
- 16 -16

Answer 57

0 and -14

Answer 58

Yeah 0 we can just ignore and we dont have to write

-7y=-14

Answer 59

so the first step is too subtract 16 on both sides because the y is still in the same place not isolated

Answer 60

dude don't go yet lol

Answer 61

@dude

Answer 62

the first step is too subtract 16 by both sides because y stays in the same place

Answer 63

if my teacher asks why am I subtracting both sides by 16 I could say "We are subtracting both sides by 16 to isolate y"

Answer 64

does that sound good ^

Answer 65

Yes

Answer 66

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Kabbed
I solved by substitution
To solve
\[x + 3y = 8 \]
\[2x - y = 2 \]
first we must
Isolate X
and then we get
\[x = -3y + 8\]
now we
Substitute x for -3y + 8 on the second equation and then simply
\[2(-3y +8) - y = 2\]
\[-6y + 16 -y = 2\]
\[-7y + 16 = 2\]
Subtract both sides by 16
\[-7y = -14\]
Divide -7y and -14 by -7
\[\frac{ -7y }{ -7 } = \frac{ -14 }{ -7}\]
\[y = 2\]

Answer 67

@dude @Shadow does what I wrote above look good and also why did we isolate x and also so were actually solving the second equation first why

Answer 68

but how does 3y become negative if we are subtracting 3y from both sides then why is it still plus @Eiwoh2 @Elsa213