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Mathematics 9 Online
xXMarcelieXx:

anyone good math proofs?

Skullmaster2017:

@dude @Vocaloid

xXMarcelieXx:

1 attachment
Skullmaster2017:

1554320925-5ca50b92216b2f6b71639400-image.png

Hero:

Suppose A = {3,4}, B = {4,5}, C = {3,4,5} then what @xXMarcelieXx

xXMarcelieXx:

arent we suppose to negate first?

Hero:

I don't see it necessary to negate anything.

xXMarcelieXx:

oh i thought we would negate when we want to disprove something?

Hero:

Nope. You just have to show that the statement is false.

xXMarcelieXx:

hmmm i have no idea whats next lol

Hero:

Try finding \(A \cup C\) and \(B \cup C\)

xXMarcelieXx:

A u C and B u C we would get an empty set ?

xXMarcelieXx:

oh wait no.. sorry i messed up

xXMarcelieXx:

A u C = { 3 , 4 , 5 } B u C = { 3 , 4 , 5 }

Hero:

So what can you conclude so far as it applies to the given statement?

xXMarcelieXx:

that they are actually the same sets

Hero:

So \(A \cup C \subseteq A \cup B\) is true. Now can we then conclude that \(A \subseteq B\)?

Hero:

Why or why not?

xXMarcelieXx:

so A is " A u C " ? sorry im confused with the notation with A c/ B

Hero:

\(A = \{3,4\}\) \(A \cup C = \{3,4,5\}\)

Hero:

\(A \subseteq B\) means A is either a subset of B or A = B

Hero:

Is that the case here?

xXMarcelieXx:

hmm its not a subset since we dont have the same sets

Hero:

A is not a subset of B because 3 is a member of A, but not a member of B.

Hero:

The End.

Hero:

BTW, it is impossible to do the proof if you're unfamiliar with the related terminology.

xXMarcelieXx:

dang thats all ? LOL Ik but i struggle with proof terminology :(

Hero:

Best to go through the definitions and organize your own notes on them. Then attempt to do the proofs.

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