Question

http://prntscr.com/n9badl

Answer 1

@Vocaloid

Answer 2

range means y-values

find the maximum y-value (if it exists) and the minimum y-value (if it exists)

Answer 3

so maximum y value is 5 and minimum y value is -1?

Answer 4

y-values, not x-values

how far down the y-axis does the red line go?

Answer 5

Oh sorry.

-5

Answer 6

(2,-9)

Answer 7

thats the range?

Answer 8

where are you getting 2 from

Answer 9

the graph has minimum at -9 and goes all the way to infinity
[-9, infinity)

Answer 10

oh without the x axis. okay so the range is only what the y axis is. got it.

Answer 11

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so this minimum -1 to infinity?

(-1, infinity)

Answer 12

closed bracket on -1 since the graph does reach -1
[-1, infinity)

Answer 13

http://prntscr.com/n9bk2m

Answer 14

domain - what are the x-values?

Answer 15

1 and 3 ?

Answer 16

keep in mind this graph covers all possible x values (no restrictions on domain)

Answer 17

so wouldnt it be infinity?

Answer 18

(-infinity, infinity) yes

in general parabolas have this domain unless there's a restriction

Answer 19

Got it

is this right? http://prntscr.com/n9blg6

Answer 20

yeah

Answer 21

http://prntscr.com/n9blqv

Answer 22

yeah that's good

Answer 23

http://prntscr.com/n9bmbj

Answer 24

-17?

Answer 25

it says two consecutive **positive** odd integers

Answer 26

17 and 15?

Answer 27

good

Answer 28

http://prntscr.com/n9bn5v
http://prntscr.com/n9bn7j

Answer 29

ugh this is kind of a pain to factor but I would just plug in x = 1 and x = 5 into each equation and see which one consistently gives you zero, since those are the zeroes on your graph

Answer 30

okay give me a min to do it lol

Answer 31

C?

Answer 32

A*

Answer 33

I also got the first answer as the solution

Answer 34

http://prntscr.com/n9brvv

Answer 35

A=W(2W)=2W^2 ?

Answer 36

good

Answer 37

http://prntscr.com/n9bsjt

Answer 38

try graphing the equation and see if it matches the picture

Answer 39

True

Answer 40

good

Answer 41

http://prntscr.com/n9bt2o

Answer 42

False?

Answer 43

yeah that's what i got too

Answer 44

http://prntscr.com/n9btvx

Answer 45

good

Answer 46

http://prntscr.com/n9bts5

Answer 47

start with

y = a(x-h)^2 + k

plug in the vertex (h,k)
plug in one of the zeros
solve for a

Answer 48

http://prntscr.com/n9bv9w

is this right?

Answer 49

yeah your final equation is correct

Answer 50

http://prntscr.com/n9bvq0

Answer 51

your equation is right but your work is a bit unclear

Answer 52

there's something unclear about the first three lines

y = a(x+10), how does this become (x+8) = a(x^2 + 18x + 80)