Question

chemistry Help

Answer 1

Given the following equations, calculate the ΔH of reaction of ethylene gas (C2H4) with fluorine gas to make carbon tetrafluoride (CF4) gas and hydrogen fluoride gas. Show your work.
H2 (g) + F2 (g) → 2HF (g) ΔH = –537 kJ
C (s) + 2F2 (g) → CF4 (g) ΔH = –680 kJ
2C (s) + 2H2 (g) → C2H4 (g) ΔH = +52.3 kJ

Answer 2

The reaction is
\[C _{2}H _{4}+6F _{2} \rightarrow 2CF _{4}+4HF\]
Using Hess's Law

\[ Delta H = \sum_{?}^{?} products-\sum_{?}^{?} reactants\]
\[ Delta H = 2*(-537)+2*(-680)-52.3\]
\[=-2487.2kJ\]

Answer 3

can you please tell me how you got to it did you use these

H2 (g) + F2 (g) → 2HF (g) ΔH = –537 kJ
C (s) + 2F2 (g) → CF4 (g) ΔH = –680 kJ
2C (s) + 2H2 (g) → C2H4 (g) ΔH = +52.3 kJ