Question

Help in geometry

Answer 1

Hi there :)

we want a line that is parallel to the given line

what do we know about the slopes of lines that are parallel to each other?

Answer 2

this source can give you a clue :)
https://www.mathsisfun.com/algebra/line-parallel-perpendicular.html

Answer 3

There are multiple ways to write equations of lines. The first format you will look at is slope-intercept form. Slope-intercept form is y = mx + b, where m is the slope, and b is the y-intercept. In order to write an equation in slope-intercept form, you must have the slope and the y-intercept. If you are not give one or both of these values, then you will need to find them using two points on the line. For example, let’s write the equation in slope-intercept form of the line CD in the previous section. Given the two points, C(5, 5) D( 9, 6), you were able to find the slope using the slope formula. This is the first step in writing the equation of the line. To find the y-intercept, choose either point and plug it into the equation. Since both points are from the same line, they should result in the same y-intercept if solved correctly. Btw u went full on teacher Oh....when U become Mod?? o.O

Answer 4

I'm kinda confused by what you've written, it doesn't look like what you're saying is related the question you are talking about
but you're right about the main idea, we need to be able to write the equation of the line we want into "slope-intercept form"

for that, we need the slope

so how do we get the slope of the line?

Answer 5

In truth, no clue

Answer 6

have you heard this before: \(Slope=\large\frac{rise}{run}\)

Answer 7

No I've missed all my classes XD

Answer 8

alright, no problem
so slope basically means how "steep" it is

like, if you're looking at a line from left -> right
if the line is "going down", it is like you're walking down a hill
=> this means the slope is negative

Answer 9

by this same logic, if you're walking up hill, the slope is positive

Answer 10

does this make sense so far?

Answer 11

Then, looking at the picture of your problem, do you think your Slope is positive? or negative?

Answer 12

@slipknot3066 you still here?

Answer 13

Yeah sorry my connection is funny

Answer 14

it's ok

what do you think about the slope of your problem?

Answer 15

Its a negative slope

Answer 16

perfect!

not too hard right?


now when people talk about slope being "rise over run"
they're talking about How steep it is, like, are you climbing a mountain, or walking up a nice hill

this is where the numbers come in

Answer 17

so in the picture example, I drew the "slope" as going Down by 2 feet for every 3 feet to the right
and since it's going down, the slope is negative so we have \(-\large \frac{2}{3}\) as the slope

Answer 18

IN you're question, we have this picture

what do you think the slope is in this case?

Answer 19

uhhh 5/12?

Answer 20

YUP! exactly :)

and remember it's a negative slope, because it looks like we're walking downhill

so \(Slope = -\large\frac{5}{12}\)

Answer 21

cool, so we have the first part done; we're almost there

like I mentioned when we first started, the slope of "parallel" lines are the same

so the slope of the line we want is also \(-\large\frac{5}{12}\)

Answer 22

but the line we want is different from the line we see

the line we want is going through the points (-5, 10) on the graph

Answer 23

so to deal with this, you mentioned the "slope intercept form" before

this is \(y = mx +b\)
where \(m = slope\)

Answer 24

we just found the slope
so our equation now looks like this
\(y=(-\frac{5}{12})x + b\)
do you see where I put the slope we just found?

Answer 25

yea

Answer 26

now, for a proper equation, we want \(b\) to be actually a number, not just a letter

so to do that, we will Temporarily "plug in" the given point (-5, 10) for (x, y)
this means \(x = -5\) and \(y=10\) temporarily

Answer 27

so it will look like this:

\((10) = (-\frac{5}{12})*(-5) + b\)

now we have to try to solve for \(b\)
do you know how to do this? :)

Answer 28

not really no

Answer 29

ok, then I'll start off with an easier example

have you seen something like
\(5 = 2 + b\)
before?

Answer 30

yeah

Answer 31

cool, what would you do in that easy case?

Answer 32

what I mean to ask is,
\(5 = 2 + b\)
what does \(b\) equal?

Answer 33

3...duh

Answer 34

haha nice nice xD

so now for the harder question

\(10 = (-\frac{5}{12})*(-5) + b\)

Answer 35

first we do \((-\frac{5}{12})*(-5) = ~?\)

Answer 36

2 u 1/12

Answer 37

awesome :)

then what does \(b\) equal?

\(10 = 2 \frac{1}{12} + b\)

Answer 38

something to equal 10 lol One sec

Answer 39

Desmos has no answer for me "We only function with x and y vairables" smh

Answer 40

haha
how did you get \(b = 3\)
from \(5 = 2 + b\)
?

Answer 41

it's the same idea

Answer 42

is it really 3....

Answer 43

nah nah nah, I'm just asking how you got it

Answer 44

Using common sense!! Something I lack

Answer 45

so just cancel out the 1/12 and use 2 + 8 -_-

Answer 46

ahaha

well the idea for \(5 = 2 + b\)
is that \(5 - 2 = 3 = b\)


so in the harder question
\(b = 10 - 2\frac{1}{12}\)

Answer 47

Idk....smh

Answer 48

you got pretty close with 2+8

\(10 - 2\frac{1}{12}\)
\( = 10 - 2 - \frac{1}{12} \)
\(=8 - \frac{1}{12}\)
\( = 7 \frac{11}{12}\)

Answer 49

SON OF A!!! i literally had that on my.. let meh show

Answer 50

hahaha seeee you've got good common sense, you just gotta believe in yourself ;P

Answer 51

haha yup, you got it!

Answer 52

-dies-

Answer 53

so overall we plug this into the "slope intercept form"

and we get
\(y = - \frac{5}{12}x + 7\frac{11}{12}\)

Answer 54

^ and that's it

sure it might have taken a while, but usually, your teacher is going to keep on asking you similar questions
so it's better to just take some time to understand what's actually going on, to make the future questions a lot easier ^_^

Answer 55

Tru tru. Ty btw...Most ppl wouldn't of taken the time to help someone as slow as me

Answer 56

it's no problem, most people would have left and shouted at me for not "giving them the answer already"
I really enjoyed helping you out, if I'm ever online again, feel free to tag me for more help ^_^