Please help asap!!
What i would do is count the number of seats in the fourth row, which has 13 seats. Keep doing this trick/technique until you get to get to the twenty-fourth row
Then do I add all the numbers up?
I'm sure there is a much more elegant way to do this.... buuuuuut. If the first row starts at 10, and it has 24 rows, then you'll need to add it like this: 10+11+12+13+14+15+16+17 ETC Essentially increment +1 for every row (24 times) and add all the numbers up
Okay and could you guys explain this...
That one i am confused on, sorry...
It's okay thanks for your help tho
you're welcome. but thank Ultri more, because he a better job of explaining them
Oh... Looking at it a second time it looks like it's every other odd number starting at 7. So it's like the first one but instead you need to increment from 7 by 4 every time and add it all together
(26 times)
So... 7+11+15+19+23+27... Now I have have no idea what I'm doing
Yea, and just keep incrementing until you have done it 26 times. Frankly I would write some code like this for it: ```javascript x = 7; for (i=0;i<=25;i++) { x += 4; } console.log(x); ``` There is probably a mathematical way to do it though
Oh okay. Thank you I understand!!
Thank you both for the help! @Ultrilliam @MrMudd183 I appreciate it a lot!
No problem! :)
just looking at the coding stuff has me confused Ultri, but i kind of under stand it. and you're welcome Hanna!
understand*
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Ultrilliam I'm sure there is a much more elegant way to do this.... buuuuuut. If the first row starts at 10, and it has 24 rows, then you'll need to add it like this: 10+11+12+13+14+15+16+17 ETC Essentially increment +1 for every row (24 times) and add all the numbers up \(\color{#0cbb34}{\text{End of Quote}}\) The simpler way would be to use the following formula: \(\large\bf{S_{n}=\frac{n}{2}(2a+(n-1)d)}\) n = total count of terms a = first term d = common difference
what blackghost said
and ultri
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