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TheDarkMessiah:
How many grams of ammonium chloride is necessary to prepare a 1.2m solution with 3.78 kg of water? Edit
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Vocaloid:
1.2m means 1.2 molal, which is 1.2 moles of solute per kg of solvent they already give you kg of water so we can set up 1.2 = (x moles ammonium chloride)/(3.78 kg of water) solve for x first then multiply by the molar mass of ammonium chloride to get grams
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