Mathematics
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Nicole:
http://prntscr.com/noh6hx
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Nicole:
@Narad
Narad:
It is false, the answer is
\[(1/2)^{3}=0.125\]
Narad:
\[7* \log _{7}4 =7*\ln4/\ln7\approx5\]
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Narad:
The equation is
\[y=2^{x+1}+3\]
Option D
Narad:
The range is
\[ y \in [2, +\infty )\]
Narad:
The money in the account will be
\[=P*e ^{rn} = 3000*e ^{0.025*5}=3399 $\]
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Narad:
\[2\log _{3}5+ \log _{3}2= \log _{3}25+\log _{3}= \log _{3}75\]
Narad:
there is 2 missing
Nicole:
wheres the 2 thats missing?
Narad:
\[=\log _{3}25*2=\log _{3}50\]
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Nicole:
so its 50 not 75?
Narad:
yes
Narad:
\[x ^{6}=100=10^{2}\]
\[6\log _{10}x=\log10_{10}10^{2}=2\]
\[\log _{10}x=2/6=1/3\]
Narad:
There is a 10 in excess
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Nicole:
okay but the final answer is log10x=2/6=1/3?
Narad:
yes
Narad:
\[-2\log _{8}(x+1)=-8\]
\[\log _{8}(x+1)=2\]
\[x+1=8^{2}=64\]
\[x=63\]
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Narad:
There is a correction
x=8^4-1=4095
Narad:
\[7\log _{9}(x+8)=7\]
\[\log _{9}(x+8)=1\]
\[x+8=9^{1}=9\]
x=1
Narad:
true
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Narad:
True
Narad:
\[\log _{2}(4*3) = \log _{2}12\]
Narad:
False
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Narad:
True
Narad:
true
Nicole:
okay thanks so much
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Narad:
You are welcome