Question

A 3.6059 g sample of a hydrate of MnSO4 was heated to drive off all of the water of hydration. The remaining solid weighed 2.4410 g. If MnSO4·x H2O represents the formula of the hydrate, then what is the value of x ?

Note: The notation MnSO4·x H2O indicates that there are x moles of H2O for every mole of MnSO4 in the solid hydrate.

Answer 1

@Vocaloid

Answer 2

2.4410 g MnSO4 after all the water is heated away
convert this to moles MnSO4

(3.6059 g - 2.4410 g) gives you grams of water that was driven away
convert this to moles water

then find the ratio between moles MnSO4 and moles water to find the hydrate formula

Answer 3

2.441 g MnSO4 x 1 mol / 151.01 = 0.0161545 mol MnSO4

3.6059 g - 2.4410 g = 1.1648 g. How would I convert this to moles of water? What is the formula?

Answer 4

divide grams by molar mass of water

Answer 5

1.1648 g x 1 mol / 18.016 = 0.06465 moles H2O

Answer 6

good, keep going

Answer 7

So, the ration would be 2 H2O / 1 MnSO4 ?

Answer 8

ratio*

Answer 9

hm?

0.06465 moles water / 0.0161545 moles MnSO4 is closer to 4 not 2

Answer 10

Ohh, right. I did something else. Oops
So, yes, 4.002 which basically is 4

Answer 11

good so 4 is your solution

Answer 12

Ight, thank you for your time!