Question

n^2*2n^3/(2n^4)^3

Answer 1

@Vocaloid

Answer 2

first step would be to expand this first (2n^4)^3 before moving on

when you have an exponent on the outside of a term, everything inside the parentheses gets applied to the exponent

so (2n^4)^3 ---> (2^3 * n^12)

Answer 3

\[n^2*2n^3/(2n^4)^3\]

Answer 4

Okay

Answer 5

then, we have

n^2*2n^3/(2^3 * n^12)

just looking at the coefficients we have 2/(2^3)
and for the variables we have (n^2 * n^3) / (n^12)

apply the exponent rules on both of these expressions and combine the result

Answer 6

Huh

Answer 7

So I multiply?

Answer 8

so starting with

2/(2^3), subtract top exponent minus bottom exponent ---> 1 - 3 = -2

2/(2^3) = 2^(-2)

Answer 9

(2 implies 2^1, if there's no exponent it's assumed to be 1)

Answer 10

1/4^7n?

Answer 11

almost, 1/(4n^7)

Answer 12

Yes I flipped them, my bad