Question

2x^4*4^-4/(2x^3)^-3

Answer 1

16x^9? @Vocaloid

Answer 2

hm, I'm not sure

2x^4*4^-4/(2x^3)^-3

we can bring the (2x^3)^-3 into the numerator and remove the negative sign from the exponent

2x^4*4^-4 * (2x^3)^3

expanding the (2x^3)^3 gives us 2^3 * x^9

2x^4*4^-4 * 2^3 * x^9

Answer 3

separating coefficients from variables

2 * 4^-4 * 2^3
and
x^4 * x^9

Answer 4

should be straightforward from there

(assuming I'm interpreting the original format correctly)

Answer 5

I got 16x^9?

Answer 6

yeah that's not what I got

2 * 4^-4 * 2^3 ---> 1/16
and
x^4 * x^9 ---> x^13

--> (x^13)/16

Answer 7

Oh

Answer 8

Whoop whoop I get to tell my teacher he's wrong >:)

Answer 9

may I see the original formatting of the problem?

Answer 10

Yes

Answer 11

\[\frac{ 2x^{4} \times x^{-4} }{ (2x^{3})^{-3} }\]

Answer 12

I'm sorry, I know what I wrote looked confusing now.

Answer 13

oh

in that case your original answer was good

Answer 14

Oh

Answer 15

anyway I can't really stay long, if you need to check your work you can just plug your problems into wolframalpha.com or mathway for the simplified solutions (make sure to format correctly 'cause these programs are very particular)

Answer 16

Oh, okay, thank you for your help!!