http://prntscr.com/nwp8h3
@Narad @Vocaloid
the shaded area represents all the solutions to the inequality so if (3,-1) is within the shaded area, it's true, otherwise false
So its true
good
B?
yep
false?
The point (0,2) lies on the edge of the shaded region. Are the red lines dotted or continuous?
Ohhh its true
Yes
D?
The system of equations is \[x \le -3\] \[y \ge 0\] This is the shaded part. The answer must be option A (?)
The system of equations are \[x \le 2\] \[x \ge -5\] \[y \ge -1\] \[y \le 6\] The correct option is option C
The equations are \[y-x \ge 4\] \[y-3x \ge-2\] Rearranging the equations \[3x-y \le2\] \[x-y \le-4\] The answer is option B
The equations of the lines are \[x \ge 2\] \[x+ 2y \ge 4\] The shaded zone corresponds to option A
The equation of the lines are \[x \ge -1\] \[x+y >3\] The answer isoption A
The equations of the lines are \[y-x \le -4\] \[y+x \le 1\] The answer is option A
The equations of the lines are \[x+y < -2\] \[4y-x >0\] Rearranging the equations The answer is option D
The equations are \[x+2y+z=5\] \[2x-y+z=4\] \[3x+y+4z=1\] Plugging the possible solutions The solutions are (5,2,-4) The answer is option A.
The equations are \[2x+y+z=5\] \[4x-2y-z=0\] \[3x-y+2z=6\] The only solution is (1,1,2) This is option A
The equations are \[x-2y-3z=3\] \[3x+y+z=12\] \[3x-2y-4z=15\] The solution is (3, 9, -6) This is option C
The equations are \[2x-y-z=3\] \[4x+y-2z=3\] \[-x+y+z=1\] The solutions are (4,1,-6) This is option C
The equations are \[2x+3y+3z=5\] \[4x+5y+3z=13\] \[3x+2y-2z=13\] The solutions are (1,3,-2) The answer is option D
The equations are \[3x-y+2z=6\] \[-x+y=2\] \[x-2z=-5\] The solutions are (1,3,3) This is option B
The equations are \[x+10y-2z=20\] \[5x-3y+4z=8\] \[2x+y=6\] The solutions are (2,2,1) The answer is option C
Let the smallest angle = x The greatest angle = x+75 Let the remaining angle = y Therefore, 1/3(x+x+75) =y and 2x+75+y=180 Solving for x and y \[2x+75=3y\] \[2x+75+y=180\] \[4y=180\] \[y=180/4=45º\] \[x=30º\] The angles are 30º, 45º, 105º The answer is option A
Let the numbers be x, y and z The equations are \[x+y+z=4\] \[y-z=x\] \[z+4y=x\] The solutions are (5, 2, -3) This is option C
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