Question

Fe(s) + 2HNO3(aq) → H2(g) + Fe(NO3)2(aq)
If 0.0975 g of solid iron react, how many moles of iron(II) nitrate are produced?

Answer 1

@Tranquility

Answer 2

So far I have been able to convert from g to mol, and what I got was \[1.7\times10^-3 mol\]

Answer 3

wait i need 3 sig figs, give me a second to correct this mistake

Answer 4

it would be 1.75 rather than 1.7

Answer 5

That's correct! Don't forget the *10^-3 part however

1.75*10^-3 moles also is the same as 1.75 mmol

Answer 6

I was just too lazy to type that out again but that's what I meant XD

Answer 7

But how to we get from just mol Fe to iron II nitrate?

Answer 8

wait...is there 2 NO3 per Fe? and we use this information to figure out how many mol of NO3 we need, and then add?

Answer 9

Fe(NO3)2 is an ionic compound so it doesn't affect how many moles

We look at the coefficient before it to determine the mole ratio
When there is no number, that's basically a hidden 1 there

For 1 mole of Fe(s), we're making 1 mole of Fe(NO3)2(aq)

Answer 10

so the answer is just 1.75x10^-3 mol?

Answer 11

Yes

Answer 12

Thank you so much!

Answer 13

No problem!