Mathematics
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Nicole:
http://prntscr.com/o01ijl
6 years ago
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Nicole:
@Narad
6 years ago
Narad:
This is the same angle
angle ACB = mAB
You can convert the angle to radians as
\[=\frac{ \pi }{ 180 }* \thetaº\]
6 years ago
Nicole:
so 102/180?
6 years ago
Narad:
don't forget to multiply by \[\pi\]
6 years ago
Nicole:
can you show me how the equation would look with the numbers plugged in
6 years ago
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Narad:
\[\frac{ 102 }{ 180 }*\pi\]
6 years ago
Nicole:
okay so the answer is \[\frac{ 17π }{ 30 }\]
6 years ago
Nicole:
thats it?
6 years ago
Narad:
Yes
6 years ago
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Narad:
The angle subtended at the center of the circle is =360º
And you have
angle ACB + angle ADB =306º
From this you can calculate angle ADB
6 years ago
Nicole:
so \[\frac{ 360 }{ 180 }*\]
6 years ago
Nicole:
π
6 years ago
Narad:
first, calculate
360º-306 and then convert to radians
6 years ago
Nicole:
thats 54
6 years ago
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Narad:
Then convert this angle in radians
6 years ago
Narad:
Have you studied radians?
6 years ago
Nicole:
\[\frac{ 3\Pi }{ 10 }\]
6 years ago
Narad:
no,
\[\frac{ 54 }{ 180 }*\pi\]
6 years ago
Narad:
Your answer is correct
6 years ago
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Narad:
The angle subtended at the center of a circle by a chord is twice the angle subtended at the cicrcumference of the circle by the same chord.
\[2x= 360 -(x+45)\]
Solve this equation for x?
6 years ago
Nicole:
x=105
6 years ago
Narad:
Yes
6 years ago
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Narad:
nº4
The angle subtended by a chord is the same at any point on the circumference.
Therefore,
\[x+2=3x-40\]
Solve this equation for x?
6 years ago
Nicole:
x=21
6 years ago
Narad:
Yes
6 years ago
Narad:
nº5
\[QR= LN\]
\[5x-7=3x+9\]
Solve this equation for x?
Then, calculate
\[5x-7\]
6 years ago
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Nicole:
x=8
6 years ago
Narad:
yes, continue
6 years ago
Nicole:
then 33
6 years ago
Narad:
yes
6 years ago
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Narad:
nº6
\[QR= LN\] and
\[OP= VW\]
Therefore,
\[x+y=6\]
and
\[3x-y=10\]
Solve for x and y in the 2 equations?
6 years ago
Nicole:
x=10/3+y/3
y= -10+3x
6 years ago
Narad:
No, add the 2 equations
6 years ago
Nicole:
10/3+y/3 + -10+3x ?
6 years ago
Narad:
No, the original equations
6 years ago
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Nicole:
x+y=6 + 3x−y=10
6 years ago
Narad:
Not like that
\[x+y=6\]
\[3x-y=10\]
\[x+3x+y-y=6+10\]
6 years ago
Nicole:
x=4
y=4
6 years ago
Narad:
ok for x,
Check for y?
6 years ago
Nicole:
still getting 4
6 years ago
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Narad:
no, from the first equation
6 years ago
Nicole:
2
6 years ago
Narad:
yes, this method of solving simultaneous equation is called
by elimination
6 years ago
Nicole:
got it
so x = 4
and y=2
final?
6 years ago
Narad:
yes
6 years ago
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Narad:
nº7
\[QR=LN\]
\[OP=VW\]
\[2x=y+12\]
\[3x=19+y\]
Solve for x and y in the 2 equations?
6 years ago
Nicole:
in the first equation
x=y/2 +6
y= 2x-12
6 years ago
Nicole:
second equation
x= 19/3+y/3
y= 3x-19
6 years ago
Narad:
then,
y(1st)=y(2nd)
6 years ago
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Nicole:
show me how it would look like please?
6 years ago
Narad:
\[2x-12=3x-19\]
6 years ago
Nicole:
x=7
6 years ago
Nicole:
but we have to find y
6 years ago
Narad:
yes, now y=?
6 years ago
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Nicole:
4?
6 years ago
Narad:
no,
6 years ago
Nicole:
?
6 years ago
Narad:
y=2x-12
6 years ago
Nicole:
do we solve 2x-12?
6 years ago
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Narad:
x=7
then y ?
6 years ago
Nicole:
6?
6 years ago
Narad:
\[y=2*7-12= \]
6 years ago
Nicole:
14
6 years ago
Nicole:
14-12=2
6 years ago
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Narad:
14-12 =?
6 years ago
Nicole:
2
6 years ago
Narad:
Yes
y=2
6 years ago
Narad:
nº8
\[AB=BC\]
\[3x+2= x+12\]
Solve for x?
6 years ago
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Nicole:
x=5
6 years ago
Nicole:
right?
6 years ago
Narad:
Yes
6 years ago
Narad:
Give me some time to think about this?
6 years ago
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Nicole:
OOkay
6 years ago
Narad:
nº9
In the triangle AEB
\[45+70+180-x=180\]
Solve this equation for x?
6 years ago
Nicole:
x=115
6 years ago
Narad:
nº10
Let angle A=x
In the triangle ABE
\[x+180-\frac{ 53 }{ 2 }+4=180\]
Solve this equation for x?
6 years ago
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Nicole:
x=45/2
6 years ago
Nicole:
right?
6 years ago
Narad:
Yes
6 years ago
Narad:
A parallelogram is a quadrilateral (four sided plane figure) with 2 pairs of parallel sides.
6 years ago
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Narad:
nº2
A square is regular quadrilateral, it has four equal sides and four equal angles (90º)
6 years ago
Narad:
A rectangle is parallelogram where all the angles are right angles, one with adjacent sides of unequal length.
6 years ago