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@Hero @Vocaloid
Hi @Nicole do you know the formula for Inscribed Angle?
If so, what is it?
Hello, im not sure could you tell me it?
The formula for inscribed angle is: \(\boxed{\text{Inscribed Angle} = \dfrac{1}{2}\text{Intercepted Arc}}\)
So in this case, what angle represents the inscribed angle and what is the intercepted arc in this case?
the inscribed angle is x+2 ?
im not sure what the intercepted angle is
Correct, the inscribed angle is C which measures x + 2 degrees. read the question once more. Remember that the inscribed angle is what intercepts the corresponding arc on a circle.
|dw:1560788890213:dw| Suppose in this case for example that E represents the intercepted angle. Then CD is the arc.
intercepted arc* that is
would it be 16x?
im not sure what the intercepted arc is
Yes, AB is the intercepted arc which is 16x degrees. So how should we set this up to solve according to the formula?
x+2=1/2(16x) ?
Exactly
x=2/7
Looks right
@Hero
What is the relationship between the central angle and the minor arc that it intercepts?
360-80 ?
You've applied the formula for finding the major arc. What I asked, however, is about the relationship between the central angle and the minor arc.
Let's do it this way: What is the central angle of the circle?
Umm no im not sure
The central angle of the circle is the angle whose vertex is the center of the circle and whose endpoints are on the circle.
Do you see something like that in the given figure?
Yes I do
@Hero
And what is the name of that angle?
C
What is the full name of the angle?
angle ACB?
Correct and what is the name of the arc that this angle intercepts?
Would you like a hint?
Yes please
The endpoints of the angle are also the endpoints of the intercepted arc. For example: |dw:1560794028685:dw| In this case, the angle XZY is the central angle and XY are the endpoints of the angle which are also the endpoints of arc XY.
Also, just so you know, in general, the measure of the central angle is equal to the measure of its intercepted arc.
That applies in the case of the problem we're working on.
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