if L is the length of each string, what is the maximum height of ball E in trial 1, above the lowest position, in terms of L? (pic below)
considering no loss of energy and elastic collision the Ball E should rise up to the level from which ball A is released
the momentum that Ball A transfers to ball B is all in horizontal direction so all the energy transferred is converted into kinetic |dw:1563320288035:dw|
had the momentum transfer been in the direction of the arrow show above there'd be some energy loss because there is no motion possible in the y direction unless the string is elastic but in our case the momentum transfer is purely in the x direction so theres no energy loss
how would I solve for h in terms of L and theta?
you're gonna have to use trigonometry for that
|dw:1563320657835:dw| have something like this set up but forgot how to proceed from here
you can use \(\cos(\theta)\) to find h
oh duh now I see it cos(theta) = (L-h)/L Lcos(theta) = L - h h = L - Lcos(theta)
thanks
np
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