The function f(x) = 4(2)x represents the growth of a butterfly population every year in a remote swamp. Jan wants to manipulate the formula to an equivalent form that calculates five times a year, not just once a year. Which function is correct for Jan's purpose, and what is the new growth rate?
f(x) = 4(1.15)x; growth rate is 5% f(x) = 4(1.15)5x; growth rate is 15% f(x) = 4(2)x; growth rate is 200% f(x) = 4(2)x, growth rate is 5%
I can narrow it down to B or C.
whats your thoughts moreso?
\(\color{#0cbb34}{\text{Originally Posted by}}\) @moreso \(\color{#0cbb34}{\text{Originally Posted by}}\) @moreso \(\color{#0cbb34}{\text{Originally Posted by}}\) @moreso \(\color{#0cbb34}{\text{Originally Posted by}}\) @moreso we can use the identity \[ \large 4(2)^{x} = 4(2)^{\frac 1 5 5x} = 4(1.15 )^{5x} \] \(\color{#0cbb34}{\text{End of Quote}}\) \(\color{#0cbb34}{\text{End of Quote}}\) \(\color{#0cbb34}{\text{End of Quote}}\) \(\color{#0cbb34}{\text{End of Quote}}\)
unless the answer choices I found are wrong( which I don't think is accurate) I believe B would be the answer to this question no?
yes b) seems correct, how did you get the choices?
I see. I missed the rest of your answer.
but we have to be careful how we define x, is x in units of years, or units of fifth of a year
I searched online and found 3 earlier questions on question cove with these choices included
I often do that when an incomplete question is posted.
the growth rate is definitely 15% so then b) does make sense
nice :)
Its worked so far
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