Math question help.
How do i find the domain of this function..\[F(x) = \frac{ 2x }{ \sqrt{x-1} }\]
Sorry, i need the range of ^^^^ function.
I’ve predicted that the range has to be equal or greater than 2.
2?
The x-value fron the domain which is *x can be equal to or greater than 1* doesn’t apply to the range...everytime i plugin 1 in the denominator i get an undef...so y has to be greater or equal to 2 for range
Do you want me to write out the answer fer?
But here it cant equal 1 either, itll make the denominator 0
Range would be 4
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Sorry my internet is dying,,, it stops for no apparent reason
Do you wanna finish this question or move on to the next topic?
Did I not help you with this one already?
Pretty sure I did
And you made the same mistake as before
I’d go back and see what i did to find the range but i can’t find my last post
I said to find the range, solve this \(x - 1 > 0\)
and NOT this \(x - 1 \ge 0\)
You told me you knew the difference between \(> and \ge \)
Yeah my bad... lol
Also, you should know that \(x \ne 1\) for this because that would lead to a zero denominator
Let me fix it
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@Ferredoxin4 already told you what the range was
And you still don't know how to write the domain correctly.
Since there’s no HA, does that mean there’s no restrictions in the range?
Can u show my how the range would be 4?
[a, b] means \(a \le x \le b\) and a and b are included in the domain. (a , b) means a < x < b and a and b are excluded from the domani.
The range is \([4, \infty)\)
How do u algebraically figureout the range
You can't always figure out the range algebraically which is why I tried to help you focus on finding the values of the lower and upper bounds
I see
So in this case, how to start thinking about finding the range is to start with \(x = 1\) you know that is undefined so the next number to try is \(x = 2\)
And evaluate f(2). You get 4 which is the lower bound.
I don’t get 4 when I plugin 2 let me try again
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So the upper bound is infinite?
I don’t see any limits when x is bigger than 2...
I get it ..let me do the range now
Bro, we're already doing the range. SMH
And you already found the domain. Remember?
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You also need to learn the difference between using [ and using (
I think that some of your Algebra 2 and Precalculus skills are rusty. I suggest you go over: -graph transformations -Parent functions -boundness, restrictions, discontinuity
AND function notation and other notation like Hero said. There's a difference between [ and (
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Hero [a, b] means \(a \le x \le b\) and a and b are included in the domain. (a , b) means a < x < b and a and b are excluded from the domani. \(\color{#0cbb34}{\text{End of Quote}}\)
So what am I doing wrong?
Hero, i’ve Told u 100 times, use simple language and terms..
It makes the problem 100 times harder for me..
Can you evaluate \(f(\infty)\)
No
Okay, then you need to use a parentheses for it so write \([4, \infty) \)
That’s it. I’ll remember that..
And that also corresponds to \(4 \le x < \infty\)
4 is inclusive and infinity is exclusive
Meaning 4 is included in the solution set and infinity is not
Too many big words... dumb it down for me...idk what corresponding means.. use simple English..chris
Christ
\([4, \infty) \iff 4 \le x < \infty\)
Ok
or \([4, \infty) \equiv 4 \le x < \infty\)
Wait 4 is the range
Yes 4 is included in the range.
\(4 \le y < \infty)\) means that every number between 4 and infinity is included in the range.
But does domain starts from 4 tho? Or 2?
lol, I kept writing x instead of y
I’m done my head is hurting...
I wanna move on to the next topic
The range is always associated with y. Sorry about that
The next topic (most likely limits) will explore this even more at a much higher level, so you need to be strong in this.
No actually it’s about prod, sum, diff, and quotient of func
And cost n profits questions
Func*
I need someone to gimme warmup questions related to that
Let me open a new thread
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