Prove that a rational number + an irrational number is an irrational number
I will prove this by doing a proof by contradiction: Assume rational + irrational = rational. Let a,c be rational, b be irrational. Then a + b = c Since a and c are rational, we can pick integers p,q,r,s such that a = p/q, c = r/s Thus p/q + b = r/s Then b = r/s - p/q Then b = (rq - sp) / sq Then b = rational since (rq-sp)/sq is integer/integer which is rational. But b is defined to be irrational so this is a contradiction. Therefore rational + irrational is not rational Therefore rational + irrational is irrational.
All you had to do was provide an example, you could have added an irrational square root to a rational number like 2. It would have been simpler.
But that is a good method.
@Gdeinward I wish it was that easy, but I'd lose points of I did that. I'm in Mathematical Analysis is a college-level course.
Ah, thats understood.
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