Question

math help plz

Answer 1

solve the given equation for *X* if possible.

Answer 2

@dude

Answer 3

You didn't take the natural log of both sides.
You only split the log(5x) into log(5) + log(x)

Answer 4

ok wait, let me think what to do next...

Answer 5

am i on the right track?

Answer 6

i need a hint

Answer 7

it's my powernap time...plz hurry up i can't keep my eyes open :/ *~* sorry

Answer 8

do i cancel out the e and ln? from both 5 and x?

Answer 9

you're on the right track

Answer 10

is this it?

Answer 11

No, you can't simplify logs that way.
Only this way:
\[\log_{e}(e)=1\]

Answer 12

awwww :/ wait..let me think

Answer 13

is this it?

Answer 14

am i wrong or am i wrong ?

Answer 15

lol
\[e^{\ln x} = x\]

Answer 16

yes i knw that .

Answer 17

that e and ln cancel out which equates to x

Answer 18

oh my gook..

Answer 19

this question is going to be the end of me tbh ...*~*

Answer 20

i'm getting depression and anxiety just by looking at this thing...

Answer 21

how wrong am i ?

Answer 22

can you do this question for me? i have to go take a powernap... i'll be back at around 6pm. Thanks lovely :)

Answer 23

There's 1 more step from here and you're done.\(\color{#0cbb34}{\text{Originally Posted
Just use this formula:
\[e^{\ln x} = x\]

Answer 24

the steps aren't enough for me tbh... can you expand the steps from e(lnx) = e(2-ln5). Because i really wanna see how you eln got moved and became a e^2 on the right side

Answer 25

honestly it has made me more confused than ....idk i have so many question...

Answer 26

\[e^{\ln x} = e^{2- \ln 5}\]
\[x = e^{2 - ln 5}\]
\[x = \frac{e^{2}}{e^{ln 5}} \]
\[x = \frac{e^{2}}{5} \]

Answer 27

I only used these 2 formulas:
\[e^{\ln x} = x\]
\[e^{a-b} = \frac{e^{a}}{e^{b}}\]

Answer 28

how did ln x and 2-ln5 become power all of a sudden???

Answer 29

wait, let me draw, i need to show you where exactly things got confuzzled for me

Answer 30

Hey dude, I suggest that before you dive into questions, learn and master the properties of logarithms and natural logs.

Answer 31

There are like 10 or more principles that you need to know in order to do any logarithmic relation based question. See those first and understand them well

Answer 32

And using those rules you could derive more which is helpful. Once you understand those, then do these problems and they'll make sense.

Answer 33

If \[a = b\]
then
\[e^{a} = e^{b}\]

Answer 34

Yes, he raised them based on the property he showed you above. That's why you need to learn properties and rules of log and ln before attempting these questions

Answer 35

bro, i know that property..chill. i wanna know why did he raise that e for?

Answer 36

to cancel something out or to condense something?

Answer 37

Yeah.
\[e^{\ln x} = x\]

Answer 38

i just wished he physically drew the next step once he raised both sides. all i see is e^2???

Answer 39

yes i know that law too

Answer 40

So starting from here:
\[ln x = 2 - ln 5\]
I raise both sides to the power of e:
\[e^{\ln x} = e^{2- \ln 5}\]
The left side becomes x:
\[x = e^{2 - ln 5}\]
The right side becomes a fraction:
\[x = \frac{e^{2}}{e^{ln 5}} \]
The bottom of the fraction simplifies to 5:
\[x = \frac{e^{2}}{5} \]

Answer 41

the only thing that confuses me is this..let me draw plz

Answer 42

can you give me a similar example

Answer 43

wait hold on.... did those cancel out? /.-

Answer 44

i'm so freakin stupit... i see what you did now...

Answer 45

or

Answer 46

okay lol

Answer 47

wait i think i got it... i need to go pee... sorry brb

Answer 48

\(\color{#0cbb34}{\text{Originally Posted by}}\) @mhchen
If \[a = b\]
then
\[e^{a} = e^{b}\]
\(\color{#0cbb34}{\text{End of Quote}}\)
Actually I'm not sure if this is always true. If anyone can come up with an example that disproves it, tell me.