Ask your own question, for FREE!
Mathematics 22 Online
Pixel:

Micah's gym is moving into a bigger space, where he can have more stationary bicycles and treadmills. Micah needs both stationary bicycles and treadmills in his gym. Let x be the number of bicycles and y be the number of treadmills. The number of new bicycles must be more than 13 times the number of new treadmills. Each bicycle costs $340 and each treadmill costs $670. He must spend less than $5,650. Select all of the constraints for this situation.

Pixel:

1 attachment
Pixel:

@dude

Pixel:

i know theres another answer, but i have this one for sure

Pixel:

1 attachment
Pixel:

i got another one

dude:

Oh wait is that a copy pasta fraction error? `The number of new bicycles must be more than 13 times the number of new treadmills.` is supposed to be `The number of new bicycles must be more than 1/3 times the number of new treadmills.`?

Pixel:

oh yeah i forgot about that XD

Pixel:

yes its 1/3

dude:

Well the answer is that sentence, turn it into an inequality

Pixel:

1 attachment
Pixel:

is that all or am i missing something

dude:

Well although its not the first thing people check for you should always check if the y>0 and x>0 work with the two equations Right off the bat x cannot be 0 because \(\large 0\cancel{>}\frac13y\) For y you have to note that the question states that Micah needs to build both ` Micah needs both stationary bicycles and treadmills in his gym.` This means y cannot be 0 (as well as x)

Pixel:

so did i get all of them

dude:

No y>0 and x>0 should also be selected

Pixel:

1 attachment
dude:

Good

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!