Micah's gym is moving into a bigger space, where he can have more stationary bicycles and treadmills. Micah needs both stationary bicycles and treadmills in his gym. Let x be the number of bicycles and y be the number of treadmills. The number of new bicycles must be more than 13 times the number of new treadmills. Each bicycle costs $340 and each treadmill costs $670. He must spend less than $5,650. Select all of the constraints for this situation.
@dude
i know theres another answer, but i have this one for sure
i got another one
Oh wait is that a copy pasta fraction error? `The number of new bicycles must be more than 13 times the number of new treadmills.` is supposed to be `The number of new bicycles must be more than 1/3 times the number of new treadmills.`?
oh yeah i forgot about that XD
yes its 1/3
Well the answer is that sentence, turn it into an inequality
is that all or am i missing something
Well although its not the first thing people check for you should always check if the y>0 and x>0 work with the two equations Right off the bat x cannot be 0 because \(\large 0\cancel{>}\frac13y\) For y you have to note that the question states that Micah needs to build both ` Micah needs both stationary bicycles and treadmills in his gym.` This means y cannot be 0 (as well as x)
so did i get all of them
No y>0 and x>0 should also be selected
Good
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