Question

new math question

Answer 1

How about you show the steps you did to get to the incorrect result?

Answer 2

is this one of those *what teacher wanna see is the right answer* situation?

Answer 3

there're no incorrect result..

Answer 4

i got the right answer but i was just wondering why can't i bring the -x power to the front of the log

Answer 5

You can't do that because the rule is \(\log(a^b) = a\log(b)\)

Answer 6

yes.. i'm following the same rule pal

Answer 7

Notice there is not two expressions with a sum in that process to put an x in front of

Answer 8

You're applying the rule to an expression that the rule was not meant for

Answer 9

can you explain \(\color{#0cbb34}{\text{Originally Posted by}}\) @Hero
Notice there is not two expressions with a sum in that process to put an x in front of
\(\color{#0cbb34}{\text{End of Quote}}\)
in simpler terms ?

Answer 10

Let me see if I can help you out with a clearer explanation

Answer 11

can you give me an example ?

Answer 12

Here's an example;

Answer 13

\(\log(a^b) = b\log(a)\)
\(\log(a + b^c)\) = no rule for this

Answer 14

wait one second.

Answer 15

so \(\log(a + b^c)\) cannot be simplified any further

Answer 16

Because there is a sum in the argument of the log.

Answer 17

There IS a rule for \(\log(a) + \log(b)\)

Answer 18

But not \(\log(a + b^c)\)

Answer 19

No, you can't because that expression is \(\ln(1 + e^{-x})\) There are other ways to express it to force a rule upon it but there is no rule for it as currently written. And you should learn how to use parentheses properly.

Answer 20

ight thanks.