Question

math

Answer 1

There's something missing though that can mess up your answer

Answer 2

what am i missing?

Answer 3

You need to apply parentheses at this step:
\(\ln(\sqrt{x} - [\ln(x^2(1 + x))]\)

That way you can see this:
\(\ln(\sqrt{x} - [\ln(x^2)+ \ln(1 + x)]\)

And then distribute the negative to get this:
\(\ln(\sqrt{x}) - \ln(x^2) - \ln(1 + x)\)

After this is when you can apply the power property to get
\(\dfrac{1}{2}\ln(x) - 2\ln(x) - \ln(1 + x)\)

which will be the correct answer.

Answer 4

Brackets/Parentheses are important

Answer 5

i literally wrote down the question as is....

Answer 6

there're no brackets

Answer 7

Not starting off no.

Answer 8

but yes i should add brackets in my solution.

Answer 9

There is something you do not realize about the quotient rule when you have more than one factor in the denominator.

Answer 10

Let me see if I can summarize it for you

Answer 11

if the two expressions are multiplying in the denom...they're logx + log y

Answer 12

in the numerator that is

Answer 13

\(\ln\left(\dfrac{a}{bc}\right)
= \ln(a) - \ln(bc)\\
=\ln(a) -[\ln(b) + \ln(c)]\\
=\ln(a) - \ln(b) - \ln(c)
\)

Answer 14

if they're adding and are in a bracket, they're under the same log base

Answer 15

I summarized what to do here:
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Hero
\(\ln\left(\dfrac{a}{bc}\right)
= \ln(a) - \ln(bc)\\
=\ln(a) -[\ln(b) + \ln(c)]\\
=\ln(a) - \ln(b) - \ln(c)
\)
\(\color{#0cbb34}{\text{End of Quote}}\)

Answer 16

Pay close attention to brackets and signs

Answer 17

let me write that down. thanks pal