Question

Plz check math question thank you!

Answer 1

@Hero

Answer 2

also x can't be -3 in the denominator

Answer 3

Basically, you have it right. One of the x's are vertical asymptote. The other is a removable discontinuity

Answer 4

what does *removable discont* is??? i mean i did solve a bunch of questions related to that on ilx but didnt have the energy to read through...however i did manage to get through all test questions tho

Answer 5

It's basically a graph with a hole at a point

Answer 6

open or close ?

Answer 7

open?

Answer 8

Open point

Answer 9

kkk thanks bro

Answer 10

btw the answer is -3

Answer 11

Interesting

Answer 12

x= -3

Answer 13

thats it

Answer 14

But not x = 3. Interesting.

Answer 15

Hang on a minute.

Answer 16

i dont see no x = 3 there

Answer 17

yup just x=-3

Answer 18

Ah, because the graph is linear. So of course it will only be discontinous at only the one point

Answer 19

Check this out...

Answer 20

k

Answer 21

Here's what to do next time...

Answer 22

\(f(x) = \dfrac{x^2 - 9}{x + 3}\)
Factor the numerator to get

\(f(x) = \dfrac{(x + 3)(x - 3)}{x + 3}\)

Then cancel the factor of one:
\(f(x) = \dfrac{\cancel{(x + 3)}(x - 3)}{\cancel{x + 3}}\)

Answer 23

Which will leave you with just \(f(x) = x - 3\)

Answer 24

Aah icy

Answer 25

This is equivalent to \(y = x - 3\) which is a linear function

Answer 26

but who even writes factors like that in the numerator tho???

Answer 27

After that, all you have to do is remember there will be a hole in the graph when the denominator is equal to zero.
x + 3 = 0
x = -3

Answer 28

Everybody factors like that

Answer 29

that basically mean the graph is continuous except for x = -3 rite

Answer 30

Because you have to remember difference of squares very important:
\(a^2 - b^2 = (a + b)(a - b)\)

Answer 31

Yes correct.

Answer 32

okie doker

Answer 33

Write down difference of squares. You will see it a lot in many different forms

Answer 34

That one you have to remember by heart.

Answer 35

bro i did factor in my solution tho.

Answer 36

I saw that. But difference of squares is simpler

Answer 37

okie dokie

Answer 38

thanks bro.

Answer 39

When you get to more difficult math, you'll want to have it handy

Answer 40

i'll write it down. thanks

Answer 41

omg :O

Answer 42

wouldn't it be x=3 rather than x=-3?

Answer 43

@hero sorry to bother you but can u plz look at that^^

Answer 44

Well, is that the same problem because beforehand I could have sworn x + 3 was in the denominator or is that a different problem.

Answer 45

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Hero
\(f(x) = \dfrac{x^2 - 9}{x + 3}\)
Factor the numerator to get

\(f(x) = \dfrac{(x + 3)(x - 3)}{x + 3}\)

Then cancel the factor of one:
\(f(x) = \dfrac{\cancel{(x + 3)}(x - 3)}{\cancel{x + 3}}\)
\(\color{#0cbb34}{\text{End of Quote}}\)

Answer 46

The one you did you put x - 3 in the denominator

Answer 47

the original problem has x+3 in the donom

Answer 48

even looked at the book

Answer 49

Okay

Answer 50

omg i made a mistake /.-

Answer 51

Okay very good. We already went over it then.

Answer 52

If u look at the solution i posted as a picture does contain the right question

Answer 53

Yup

Answer 54

My only questions is this... let me draw one second

Answer 55

Wouldn’t you set the x-3 = 0 and solve for x?

Answer 56

Because the textbook does say x=-3

Answer 57

You set the denominator equal to zero.

Answer 58

Then solve for x. You're making it more complicated than it is

Answer 59

Set the denominator equal to zero
\(x + 3 = 0\)
Subtract three from both sides.
\(x = -3\)

Answer 60

Can you give me another similar example? Plz

Answer 61

It's simple. You're just getting confused over signs for some weird reason.

Answer 62

I was just asking because you canceled out the (x+3) both from the numerator and denominator and the remainder was just x-3...so i thought wouldn’t we set that equal to 0 and solve for x? :/

Answer 63

But you still have to set the denominator equal to zero. x + 3 is in the denominator not x - 3

Answer 64

x - 3 is the linear expression. It has nothing to do with finding the discontinuity

Answer 65

Okie dokie. I got it. Thanks bro :) <3