Question

I have a question in regards to derivatives and differentiation...

Answer 1

what is your question

Answer 2

Why wasn’t radical considered a constant here in this example?

Answer 3

@Hero

Answer 4

\(\sqrt{2}\) is a constant. \(\sqrt{x}\) is not

Answer 5

So does that mean...i can’t convert the radical of 2 to ration and find it’s derivative from there?

Answer 6

You can convert \(\sqrt{x}\) to \(x^{-1/2}\) to find its derivative. Since the derivative of \(\sqrt{2}\) is zero, it is not necessary to convert it to exponent form.

Answer 7

Ok i think i got it now. Thanks bro

Answer 8

For the sake of curiosity....i feel like i need to ask you a question...

Answer 9

So are you telling me that if i convert the radical of 2 to rational form and apply the power rule..and get 1/2.sq(2)....that won’t be on a graph?

Answer 10

....apply the power rule and some algebra to get 1/2.sq(2)****

Answer 11

If the function is \(f(x) = \sqrt{x} + \sqrt{2}\) and then you find \(f'(x)\) then the constant will become zero which will not be on the graph of \(f'(x)\)

Answer 12

The power rule is \(\dfrac{d}{x}(x^n) = nx^{n-1}\). This implies that the power rule applies to terms with \(x\) as the variable.

Answer 13

\(\sqrt{2}\) does not include \(x\)

Answer 14

Oooooo I see now...so the power rule applies to variables... and not x values... i see now.

Answer 15

I was with you until you said "and not x values". You sound confused.

Answer 16

\(x\) IS a variable

Answer 17

When i say x-values.. i mean integers...

Answer 18

Integers/constants