Question

math help plz :)

Answer 1

find the roots/zeros

Answer 2

Well first just rule of thumb

Because x is being multiplied to everything, substituting 0 would make the whole equation 0
\(-2xe^{-x^2+4}\) => \(-2(0)e^{-(0)^2+4}\) = 0

Now algebraically (for other solutions)
\(-2xe^{-x^2+4}=0\)
\(e^{-x^2+4}=0\)
\(ln(-x^2+4)=ln(0)\)
Undefined


So we only have 0 as a root/zero

Answer 3

That’s where i was stuck...that ln(0) ... since it equates to be undefine.. i thought there are no roots because i thought when you have one side of the equation undefine, the whole thing becomes undefined.

Answer 4

Well yeah, the only thing that made it have a root of 0 was because x is being multiplied to the equation
\(\large -2\color{red}{x}e^{-x^2+4}\)


Otherwise, there wouldn't be any roots
Ex. \(-2e^{-x^2+4}\) [No roots]

Answer 5

Icy now

Answer 6

Can we do this tho to prove that x = 0???

Answer 7

Yeh that looks good