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Mathematics 15 Online
mhchen:

What is wrong with this proof: ;)

mhchen:

\[(4-\frac{9}{2})^{2} \] \[(4)^{2} - (2)(4)(\frac{9}{2}) + (\frac{9}{2})^{2}\] \[16 - 36 + (\frac{9}{2})^{2}\] \[-20 + (\frac{9}{2})^{2}\] \[25 - 45 + (\frac{9}{2})^{2}\] \[(5)^{2} - (2)(5)(\frac{9}{2}) + (\frac{9}{2})^{2}\] \[(5-\frac{9}{2})^{2}\]

mhchen:

So based on what I wrote above: \[\sqrt{(4-\frac{9}{2})^2} = \sqrt{(5-\frac{9}{2})^{2}}\] simplify that to get \[4 - \frac{9}{2} = 5 - \frac{9}{2}\] and 4 = 5 voila

Gdeinward:

I know whats wrong with this proof. It EXISTS.

mhchen:

@Gdeinward Does \(\sqrt{4-\frac{9}{2}}\) really exist?

justjm:

Also when you take the square root there is a ±.

Vocaloid:

justjm is already getting on it, but I'll re-iterate (4 - 9/2)^2 = (5 - 9/2)^2 is a true statement the left side is equal to (-0.5)^2 and the right side is equal to (0.5)^2 of course, when you take the square root, as justjm stated, you must take into consideration the positive and negative solutions of the square root.

SemiDefinite:

\(\sqrt{ \left (4-\frac{9}{2} \right )^2} = \left( \sqrt{(4-\frac{9}{2}} ~~\right) ^2\) !!!! Nothing to do w/ PEDMAS.

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