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@Hero
First, do you recall the point-slope form of the equation of a line?
y - y1 = m(x - x1)
Very good. And do you recall what m represents?
m is the slope
Correct and what is the value of the given slope for this problem?
-3
So this means we can insert -3 in place of m in the formula. Would you mind trying this?
y - y1 = -3(x - x1)
Excellent. Now the given point is \((x_1,y_1) = (3,-4)\). In other words \(x_1 = 3\) and \(y_1 = -4\)
Can you insert those values to the formula as well?
y--4=-3(x-3)
Very good, but it is more correct to use parentheses properly and write it as \(y - (-4) = -3(x - 3)\). Using parentheses helps to avoid making mistakes later.
From here you apply properties of algebra. On the left hand side, apply the property of an opposite number. -(-a) = a
On the right hand side, apply the distributive property: a(b + c) = ab + ac
so positive 4 y-4=-3(x-3) then y-4=-3x+(-9)?
If you apply the property correctly on the left hand side you should get y + 4
On the right hand side, you have to multiply -3 by x and then -3 by -3. Remember the properties of multiplying negative numbers.
The product of two negative numbers is a positive number.
but do I have to add this in my answer because it only asks for the equation in point slope form which we did and that was y−(−4)=−3(x−3)
You should at least simplify the left hand side.
So just simplify the left hand side, then you'll be done
okay got that im going to make a new post
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