Question

Which is not a step when constructing a line parallel to the x-axis of a coordinate plane through a point?

Measure the distance from the point to the x-axis

Place the compass on the point and mark an arc on both sides of the x-axis.

Connect the arc intersections using a straight edge.

Draw a transversal through the x-axis and a point not on the x-axis.

Answer 1

@dude

Answer 2

Ideas?

https://www.mathopenref.com/constparallel.html
Can help if you're unsure of the steps

Answer 3

im thinking its d?

Answer 4

No no

They drew the transversal over the point P and the x axis, so that is a step in the construction of a life

(Note on how the ruler was used measurement vs straightedge)

Answer 5

A?

Answer 6

or C

Answer 7

*It would be A*
Because they didn't measure anything

They only used the ruler to draw straight lines (it was used only as a straightedge)

Answer 8

(C was the last step in the construction)

Answer 9

Got it okay

Answer 10

If the midpoint between (18, y) and (20, -15) is (19, -5), find the value of y.

Answer 11

Make a new post after this one

Answer 12

okay

Answer 13

This is harder said than done, so I'll set it up for you, if you dont understand something, feel free to ask

Use the midpoint formula

\((\dfrac{x_1+x_2}{2}, \dfrac{y_1+y_2}{2})=(x_m,y_m)\)
I am using m as a letter to define "middle" -- this is informal

(18, y) -> (\(x_1,y_1\))
(20,-15) -> (\(x_2,y_2\))

(19,-5) -> (\(x_m,y_m\))

Substitute
\((\dfrac{18+20}{2}, \dfrac{y-15}{2})=(19,-5)\)

It could help to split it into x and y

\(\dfrac{18+20}{2}=19\)

\(\boxed{\dfrac{y-15}{2}=-5}\) We only need to solve for y

Do you know how to solve for y from here?

Answer 14

y=5

Answer 15

Ye good

Answer 16

You can check this if you want

Do you want me to show you how to check? Or are you okay?

Answer 17

no thank you I got that one. Im going to make a new post