Determine if the lines that pass through the given points are parallel, perpendicular or neither. Line A: (5, 10) and (12, 6) Line B: (-2, 4) and (5, 8)
@dude
For this you just need to find the slope between the points \(m_a=\dfrac{y_2-y_1}{x_2-x_1}\) and \(m_b=\dfrac{y_2-y_1}{x_2-x_1}\)
ma:-4/7 mb: 4/7
now what do I do
@dude
@Gdeinward
the slopes indicate that the points are located on opposite sides of the y-axis
Idealy, if you cant visualize it, you would graph the points to determine their relationship.
so parallel?
@Gdeinward am i correct?
no. Here is a grpah with the points:
but I learned that we are supposed to find the slope and base it off that
There are general rules that decide wether they ar eparralel or night. They are as follows:
perpendicular slopes are negative reciprocals of each other
the slopes of parallel lines are equal.
So if the slopes dont reciprocate any of these rules, then it must be neither.
so -4/7 and 4/7 are not parallel or perpendicular?
Yep, theyre neither They just intersect
That is correct.
Like Dude said.
oh okay and this one: Determine if the lines that pass through the given points are parallel, perpendicular or neither. Line A: (2, 3) and (-4, 5) Line B: (-4, 9) and (-3, 12)
the slopes are 2/-6 and 3/1
Well, following the previous rules, what do you think?
perpendicular
when its simplified
That is correct. Now ur getting the hang of it.
@dude
Make sure to make a new post Anyway, well this looks like a standard equation Do you know the slope of that line is?
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