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zarasht:
How many grams are in 2.57 × 10¹⁵ molecules of CO?
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justjm:
Use dimensional analysis by using Avogadro's number and then molar mass. \(2.57E15~Molecules~CO • \frac{1 mol}{6.23E23} • \frac{28.01~MM~CO}{1~mol~CO} = X~grams~CO\)
zarasht:
is the answer 1.2 grams
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