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Mathematics 13 Online
justjm:

How do I go about this using u-substitution

justjm:

\(\int_{ }^{ }x\sqrt{x+3}dx\)

justjm:

@Vocaloid @mhchen @Hero

myeyeshurt:

Let u=x+3

justjm:

I tried doing that but messed up but let me give it a try once again

justjm:

thx for responding

myeyeshurt:

You should get the (u-3)sqrt(u)=u^(3/2)-3sqrt(u) as the integrand

justjm:

\[\int\limits_{}^{} x \sqrt{u} du\] so now do I continue normally

myeyeshurt:

Nah you're subbing wrong

justjm:

Oh okay like this? \[\int\limits_{}^{} (u-3) \sqrt{u} du\]

myeyeshurt:

Yeah keep in mind that when you do u sub you need an expression for dx in terms of du

myeyeshurt:

So here u=x+3 and du=dx

justjm:

Yeah I did that Since u=x+3 du/dx = 1 so du=dx

myeyeshurt:

Yeah

myeyeshurt:

Anyways you can distribute and integrate now

justjm:

Thanks bro. So what you did is you had the u=x+3 but you changed the x from the integrand to u-3. Thanks. I was confused on how there was an x and a u.

myeyeshurt:

Yeah these u sub integrals have a tendency to hide in plain sight. Trial and error is sometimes necessary

justjm:

Ah okay. Thank you once again.

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