How do I go about this using u-substitution
\(\int_{ }^{ }x\sqrt{x+3}dx\)
@Vocaloid @mhchen @Hero
Let u=x+3
I tried doing that but messed up but let me give it a try once again
thx for responding
You should get the (u-3)sqrt(u)=u^(3/2)-3sqrt(u) as the integrand
\[\int\limits_{}^{} x \sqrt{u} du\] so now do I continue normally
Nah you're subbing wrong
Oh okay like this? \[\int\limits_{}^{} (u-3) \sqrt{u} du\]
Yeah keep in mind that when you do u sub you need an expression for dx in terms of du
So here u=x+3 and du=dx
Yeah I did that Since u=x+3 du/dx = 1 so du=dx
Yeah
Anyways you can distribute and integrate now
Thanks bro. So what you did is you had the u=x+3 but you changed the x from the integrand to u-3. Thanks. I was confused on how there was an x and a u.
Yeah these u sub integrals have a tendency to hide in plain sight. Trial and error is sometimes necessary
Ah okay. Thank you once again.
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