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Mathematics 18 Online
darkknight:

you have 500 meters of fencing with which to make 2 enclosures. One enclosure will be in the shae of a square and the other will have the shape of an isosceles right triangle. For example the enclosures might look something like this (imagine a square next to a isosceles right triangle). How long should the legs of the triangle be to minimize the combined area of the two enclosures?

Gdeinward:

are there any answer choices?

darkknight:

no

Gdeinward:

I mean it seems that you dont have to use the whole 500 yards right?

Gdeinward:

or meters

darkknight:

you do have to use the whole 500 meters

Gdeinward:

That doesnt make, sense. That means the area cant be any less than 500 meters,

Gdeinward:

so theoretically you could just do 5 times 5 for the square one, and whatevr leg lengths to compensat for the 475 meters left

darkknight:

so you have to use all 500 meters to make 2 enclosures, one in the shape of a square and one in the shape of a isosceles right triangle. You have to dimension the legs of the triangle/square to get the to have the smallest combined area

Gdeinward:

@justjm

Gdeinward:

This one gave me a brain fart XD

justjm:

The giveaway to how you need to approach is when it says 'isosceles right triangle' Are they connected?

darkknight:

no

darkknight:

so since it is a square I can make one side x, which makes the perimeter of the square 4x. I can make a leg on the isosceles right triangle y, so the perimeter of that becomes 2y+ y times sqrt of 2

justjm:

correct, now you're getting there!

darkknight:

what do I do next

justjm:

Are you allowed to use calculus or only precalculus methods?

darkknight:

I am in pre-calc. so pre-calc. only

Gdeinward:

Usually the teachers dont mind advanced usage of methematics. They definitely wouldnt change the grading

Gdeinward:

Man I cant type tonight

darkknight:

I don't know them though

Gdeinward:

True, good point

darkknight:

need help!!!

darkknight:

got the answer

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