you have 500 meters of fencing with which to make 2 enclosures. One enclosure will be in the shae of a square and the other will have the shape of an isosceles right triangle. For example the enclosures might look something like this (imagine a square next to a isosceles right triangle). How long should the legs of the triangle be to minimize the combined area of the two enclosures?
are there any answer choices?
no
I mean it seems that you dont have to use the whole 500 yards right?
or meters
you do have to use the whole 500 meters
That doesnt make, sense. That means the area cant be any less than 500 meters,
so theoretically you could just do 5 times 5 for the square one, and whatevr leg lengths to compensat for the 475 meters left
so you have to use all 500 meters to make 2 enclosures, one in the shape of a square and one in the shape of a isosceles right triangle. You have to dimension the legs of the triangle/square to get the to have the smallest combined area
@justjm
This one gave me a brain fart XD
The giveaway to how you need to approach is when it says 'isosceles right triangle' Are they connected?
no
so since it is a square I can make one side x, which makes the perimeter of the square 4x. I can make a leg on the isosceles right triangle y, so the perimeter of that becomes 2y+ y times sqrt of 2
correct, now you're getting there!
what do I do next
Are you allowed to use calculus or only precalculus methods?
I am in pre-calc. so pre-calc. only
Usually the teachers dont mind advanced usage of methematics. They definitely wouldnt change the grading
Man I cant type tonight
I don't know them though
True, good point
need help!!!
got the answer
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