Thermodynamic (1,4)addition
|dw:1576473877050:dw| I don't understand why the answer is 1,2 addition instead of 1,4
qwerty chem expert ?? :'[
Expert? No way xD
orgo is killing me. I'm diene.
I'm kinda confused with what's going on because the product neither does look like kinetically formed not does it looks like thermodynamically formed
|dw:1576525050686:dw| I think this should be the result of kinetically controlled product (when the temperature is low) But since the temperature is high we must get the thermodynamically controlled product
|dw:1576525206385:dw| Thermodynamically controlled product
I'm done with organic chem :)
i'm going to fail..
\(\color{#0cbb34}{\text{Originally Posted by}}\) @imqwerty Created with RaphaëlReply Using Drawing Thermodynamically controlled product \(\color{#0cbb34}{\text{End of Quote}}\) I think that this should've been the product because the temperature is high and so the most thermodynamically stabled product(which is this drawing) should be formed
I can't quote a drawing? @Ultrilliam
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Nnesha i'm going to fail.. \(\color{#0cbb34}{\text{End of Quote}}\) F :-)
Hmmm... that's a good point, but understandable with how it works, I might change that so it does, thanks for the feedback! :)
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Ultrilliam Hmmm... that's a good point, but understandable with how it works, I might change that so it does, thanks for the feedback! :) \(\color{#0cbb34}{\text{End of Quote}}\) Np :-)
how do we know which double bond we need to break??
For the kinetically controlled product I just picked the one which had more electron density on it- the one with more alpha hydrogens
For the thermodynamically controlled product I chose the one which was forming a more stable final product
\(\color{#0cbb34}{\text{Originally Posted by}}\) @imqwerty For the kinetically controlled product I just picked the one which had more electron density on it- the one with more alpha hydrogens \(\color{#0cbb34}{\text{End of Quote}}\) so more stable carbocation ??
see there are like 50+ things we need to keep in mind in order to solve just one question -_-
Tbh I think i'm confused and missing out on some points :l Can't really think straight rn, I'll check it tomorrow?
Thank you for trying!! appreciate it! :--)
btw any tips for synthesis ??
Wdym by synthesis
Chemical synthesis when given is the reactant and product and "100"mhmm reagents and we have to find which reagent applied
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Nnesha Chemical synthesis when given is the reactant and product and "100"mhmm reagents and we have to find which reagent applied \(\color{#0cbb34}{\text{End of Quote}}\) You have to know them all Sometimes you don't have to actually remember the exact type of reaction; just knowing the properties of the reagents and reactants is enough
Yep, whenever you're stuck- there's a YouTube video for it.
I watched that video already I think the answer key is wrong.
\(\color{#0cbb34}{\text{Originally Posted by}}\) @imqwerty Yep, whenever you're stuck- there's a YouTube video for it. \(\color{#0cbb34}{\text{End of Quote}}\) I wish i can search for a new brain as well..
thank you!
Np
the kinetically controlled product i made is wrong it should be this-|dw:1576568881024:dw|
|dw:1576568956056:dw|
|dw:1576569146457:dw| do you mean like this ?
|dw:1576569227662:dw| on the answer key this is the product given under heated(high temp) condition
like this- |dw:1576569287681:dw|
and it also says thermodynamic = most stable double bond product kinetic = most stable carbocation
|dw:1576569384237:dw| move + away on 2nd carbon
\(\color{#0cbb34}{\text{Originally Posted by}}\) @imqwerty perhaps the ans key is wrong \(\color{#0cbb34}{\text{End of Quote}}\) i think so too
nvm.. the answer given is correct the double bond in the answer is the most stable
well if we are looking for more stable carbocation product then kinetic one is correct|dw:1576569604759:dw|
yeah, that makes sense it would rearrange and form a more stable carbocation in case of kinetically controlled product
yep
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