Seth is using the figure shown below to prove Pythagorean Theorem using triangle similarity. In the given triangle ABC, angle A is 90° and segment AD is perpendicular to segment BC. The figure shows triangle ABC with right angle at A and segment AD. Point D is on side BC. Part A: Identify a pair of similar triangles. (2 points) Part B: Explain how you know the triangles from Part A are similar. (4 points) Part C: If DB = 9 and DC = 4, find the length of segment DA. Show your work. (4 points)
@Ultrilliam @Hero
|dw:1577114730095:dw|
When you are given a setup like this where you are given a right triangle where \(\triangle{ABC}\) \(\overline{AD} \perp \overline{BC}\) this means two smaller right triangles will be created which are similar to each other. To figure out the corresponding angles, you have to know that the smaller angles of angle \(A\) will add to get \(90^{\circ}\) so let the smaller angles of \(\angle A\) be \(x\) and \(y\) we know that since \(\angle A\) is \(90^{\circ}\) then \(x + y = 90^{\circ}\) |dw:1577114753772:dw|
Now we also know for the smaller right triangles, the other two angles of a triangle othar than angle \(D\) which we know is a right angle will add to 90 degrees.
So that's how we know those other angles are also \(x\) and \(y\).
And so knowing all this, how can you write the two pairs of similar right triangles? Technically you can write it as three pair of similar right triangles.
The two pear of similar right triangles is ADB and ADC? I'm not sure if this is the correct order.
You right it by matching up the angles which is X, 90, Y
is x + y = 45 + 45
So you correspond the angle name in that order.
Not necessarily. x and y are complementary angles whose sum is 90 degrees. we don't know their values yet.
ok
Care to give it another shot as far as writing the similar triangles?
ADB and CDA?
Correct
How would I find part C?
To find the measure of DA, what you have to do is setup a proportion. Let me research the term for this real fast so you know what this concept is called.
ok
The concept is called Geometric Mean
How would I use it in this problem?
Do i find the geometric mean of 9 and 4
One moment...
|dw:1577116168002:dw| To find Geometric Mean you setup the following proportion: \(\dfrac{BC}{AD} = \dfrac{AD}{DB}\)
Oops Hang on.
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Hero Created with RaphaëlReply Using Drawing To find Geometric Mean you setup the following proportion: \(\dfrac{DC}{AD} = \dfrac{AD}{DB}\) \(\color{#0cbb34}{\text{End of Quote}}\)
that equation equals: 4/AD = AD/9
Replace AD with \(x\)
oh so 4/x = x/9
Then cross multiply to solve for \(x\)
this equals 6
What equals 6?
x?
Yes but what segment equals 6
DA
or AD
Correct.
thank you
Great job
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