The diagram below models the layout at a carnival where G, R, P, C, B, and E are various locations on the grounds. GRPC is a parallelogram. Parallelogram GRPC with point B between C and P forming triangle GCB where GC equals 350 ft, CB equals 300 ft, and GB equals 400 ft, point E is outside parallelogram and segments BE and PE form triangle BPE where BP equals 200 ft. Part A: Identify a pair of similar triangles. Part B: Explain how you know the triangles from Part A are similar. Part C: Find the distance from B to E and from P to E. Show your work.
@Hero @dude @Ultrilliam
I know how to find similar triangles but the parallelogram is confusing me
and i can't find a ratio
hello? @hero
Why is the parallelogram confusing you if you already know how to find the similar triangles?
because there are 3 triangles and then i see a parallelogram and it makes me overthink. its not in a math way that it confuses me, it just the way i see it. like an illusion that has multiple things in the picture.
idk how to explain it srry
Well, there are things you already know about a parallelogram such as opposite sides are congruent.
Knowing this you can label the opposite lengths of the parallelogram
yes, that means RP is 350 ft
Then you should know that vertical angles are congruent.
so that means BE is 150?
wait..
no
No, however, there is a trick that you can do to help: |dw:1577122406905:dw|
well i know that GR is 500 because CB is 300 + BP which is 200
|dw:1577122453355:dw|
oh that creates another triangle
You can flip the triangle so that it is inside the parallelogram
It's the same triangle.
oh
So here's how you can do this...
so that means the similar triangles are GCB and EPD?
One moment. The opposite angles of a parallelogram are congruent but not necessarily the consecutive sides.
Because of vertical angles are congruent we know that these two angles are congruent: |dw:1577123106078:dw|
Also, because of alternate interior angles, you should know that angle G is congruent to angle E: |dw:1577123285175:dw|
From there we can conclude the triangles are similar.
so GCB and EPB are similar triangles
I'll agree with that
then if it is, for part c, finding the distance from B to E and from P to E i'll have to find a ratio/proportion?
Correct. Are you able to set up the proportion?
no not really
would it be like PB/EP = CP/GC
wait
im pretty sure thats wrong
Okay so try again
EP/EB = CG/GB?
what, where did that com from.
thats not right either... sorry
was my first guess close?
So here's how to do it ...
CB/CG = PB/PE
Looks right now
so now i plug it in, 300/350 = 200/x
now i cross multiply?
If you plugged everything in correctly and solve for x, you should get the correct value.
im getting decimals
What did you get?
233.333 repeating
Okay, let me check to make sure you input everything correctly.
You input everything correctly so it should be correct. 233 + 1/3 feet
ok so that means PE is 233 1/3 feet?
Yes
wait the ratio is 1.5
that means GB is 266.66 repeating
thank you
?
The ratio for 300/350 is 0.857 The ratio for 200/233.33 is also 0.857
really? im dumb
If the top number is smaller than the bottom number the ratio will be less than one.
oh
Did you find the distance from B to E?
where did you identify the triangle pairs
@Hero
What do you mean?
how did you know they were similar triangles
Because for any two triangles, if you can prove that two corresponding angles are congruent, then the third corresponding angles of will also be congruent.
okay and can you help meFind the distance from B to E and from P to E
Do you not already have what you need?
no this topic is new to me and i need help if i had everything i need and knew what i was doing i wouldn't have to ask
can you help please
Everything is explained above. The question is, 'Where are you confused?'.
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