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Mathematics 22 Online
moonwalk:

The diagram below models the layout at a carnival where G, R, P, C, B, and E are various locations on the grounds. GRPC is a parallelogram. Parallelogram GRPC with point B between C and P forming triangle GCB where GC equals 350 ft, CB equals 300 ft, and GB equals 400 ft, point E is outside parallelogram and segments BE and PE form triangle BPE where BP equals 200 ft. Part A: Identify a pair of similar triangles. Part B: Explain how you know the triangles from Part A are similar. Part C: Find the distance from B to E and from P to E. Show your work.

moonwalk:

moonwalk:

@Hero @dude @Ultrilliam

moonwalk:

I know how to find similar triangles but the parallelogram is confusing me

moonwalk:

and i can't find a ratio

moonwalk:

hello? @hero

Hero:

Why is the parallelogram confusing you if you already know how to find the similar triangles?

moonwalk:

because there are 3 triangles and then i see a parallelogram and it makes me overthink. its not in a math way that it confuses me, it just the way i see it. like an illusion that has multiple things in the picture.

moonwalk:

idk how to explain it srry

Hero:

Well, there are things you already know about a parallelogram such as opposite sides are congruent.

Hero:

Knowing this you can label the opposite lengths of the parallelogram

moonwalk:

yes, that means RP is 350 ft

Hero:

Then you should know that vertical angles are congruent.

moonwalk:

so that means BE is 150?

moonwalk:

wait..

moonwalk:

no

Hero:

No, however, there is a trick that you can do to help: |dw:1577122406905:dw|

moonwalk:

well i know that GR is 500 because CB is 300 + BP which is 200

Hero:

|dw:1577122453355:dw|

moonwalk:

oh that creates another triangle

Hero:

You can flip the triangle so that it is inside the parallelogram

Hero:

It's the same triangle.

moonwalk:

oh

Hero:

So here's how you can do this...

moonwalk:

so that means the similar triangles are GCB and EPD?

Hero:

One moment. The opposite angles of a parallelogram are congruent but not necessarily the consecutive sides.

Hero:

Because of vertical angles are congruent we know that these two angles are congruent: |dw:1577123106078:dw|

Hero:

Also, because of alternate interior angles, you should know that angle G is congruent to angle E: |dw:1577123285175:dw|

Hero:

From there we can conclude the triangles are similar.

moonwalk:

so GCB and EPB are similar triangles

Hero:

I'll agree with that

moonwalk:

then if it is, for part c, finding the distance from B to E and from P to E i'll have to find a ratio/proportion?

Hero:

Correct. Are you able to set up the proportion?

moonwalk:

no not really

moonwalk:

would it be like PB/EP = CP/GC

moonwalk:

wait

moonwalk:

im pretty sure thats wrong

Hero:

Okay so try again

moonwalk:

EP/EB = CG/GB?

moonwalk:

what, where did that com from.

moonwalk:

thats not right either... sorry

moonwalk:

was my first guess close?

Hero:

So here's how to do it ...

1 attachment
moonwalk:

CB/CG = PB/PE

Hero:

Looks right now

moonwalk:

so now i plug it in, 300/350 = 200/x

moonwalk:

now i cross multiply?

Hero:

If you plugged everything in correctly and solve for x, you should get the correct value.

moonwalk:

im getting decimals

Hero:

What did you get?

moonwalk:

233.333 repeating

Hero:

Okay, let me check to make sure you input everything correctly.

Hero:

You input everything correctly so it should be correct. 233 + 1/3 feet

moonwalk:

ok so that means PE is 233 1/3 feet?

Hero:

Yes

moonwalk:

wait the ratio is 1.5

moonwalk:

that means GB is 266.66 repeating

moonwalk:

thank you

Hero:

?

Hero:

The ratio for 300/350 is 0.857 The ratio for 200/233.33 is also 0.857

moonwalk:

really? im dumb

Hero:

If the top number is smaller than the bottom number the ratio will be less than one.

moonwalk:

oh

Hero:

Did you find the distance from B to E?

gokrazy223:

where did you identify the triangle pairs

gokrazy223:

@Hero

Hero:

What do you mean?

gokrazy223:

how did you know they were similar triangles

Hero:

Because for any two triangles, if you can prove that two corresponding angles are congruent, then the third corresponding angles of will also be congruent.

gokrazy223:

okay and can you help meFind the distance from B to E and from P to E

Hero:

Do you not already have what you need?

gokrazy223:

no this topic is new to me and i need help if i had everything i need and knew what i was doing i wouldn't have to ask

gokrazy223:

can you help please

Hero:

Everything is explained above. The question is, 'Where are you confused?'.

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