How to find percent ionization using pH at the half equivalence point?

Question

justjm · Answer

Oof, sorry the wrong subject. My browser doesn't update anymore so every time I post a question it switches down.

anyhow I did a titration lab with acetic acid and got the titration and mapped the pKa at ≈4.8, hence the pH is 4.8. My experimental Ka is 1.585x10^-5. I got my percent ionization as 1.347%, can someone check for me?

Also I had 25mL of .1M acetic acid to begin with and it reached the half equivalence point after 12.5mL of adding NaOH.

justjm · Answer

@imqwerty Hey imqwerty if you could take a look, I would really, really appreciate it! Thank you for all the help you've been offering so far!

justjm · Answer

I think I was right. I used ICE table to find the [H]eq, and [HA]i I just used .1M

imqwerty · Answer

```
Also I had 25mL of .1M acetic acid to begin with and it reached the half equivalence
 point after 12.5mL of adding NaOH.
```
How did you use this info?