real quick: if a exponential function has a vertical shift is it still exponential?
@darkknight, could you explain how it would stop being exponential as a result of a vertical shift? If it is no longer an exponential function, what kind of function is it after the vertical shift?
sorry what i meant was that it wouldn't have that standard exponential form right
If it shifts vertically, then yes only the form would change. It would no longer be in standard form. Do you have an idea of which transformation preserves the standard form?
yes sir
vertical dilations, because that would be multiplying to Ao horizontal dilations and shifts
maybe
I'm not sure about the horizontal shifts and dilations actually
Okay, Vertical dilation should be correct.
what about horizontal shifts and dilations?
shifts would effect it like this 4^x would be 4^(x-1) if shift 1 to the right
and for dilations it will be f(x/c)
so would Ao (b)^(t-1) be considered standard exponential form?
Hang on let me check something real quick
k
Actually, this is more of a trick question than originally assumed simply because the \(A_o\) part of the exponential function is technically not supposed to change as it represents the initial amount.
I'll have to get back to you on it.
oh really?
Yup, really.
very trick question then, lol
wait a minute
the question is asking "or which of the four operations is the resulting function still a standard exponential model? So technically if I do a vertical dilation by a factor of 3 then it will still be a standard exponential model right?
If you go strictly by that, then I suppose it is. I'm just going to verify it real quick
k
gtg
so i think that both types of dilations keep it in standard exponential form, but not shifts because a horizontal shift would result in b^(x-n) when shifting n units and that isn't in standard exponential form
It asks "Which of the given transformations" and that implies "Which ONE". So if I had to go with one, I'd go with vertical dilation
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