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Mathematics 21 Online
RyeBread1:

Six equilateral triangles are connected to create a regular hexagon. The area of the hexagon is 24a^2 – 18 square units. Which is an equivalent expression for the area of the hexagon based on the area of a triangle?

RyeBread1:

Help me! Im being timed!!! I failed twice already and this is my last chance!!

imqwerty:

what are the options

RyeBread1:

hold on give me a second

imqwerty:

aight

RyeBread1:

A. 6(4a2 – 3) B. 6(8a2 – 9) C. 6a(12a – 9) D. 6a(18a – 12) Here they are

imqwerty:

|dw:1582392796039:dw|

imqwerty:

your figure will look something like this

RyeBread1:

i dont have a figure i just have those options that I gave you. They re just numbers no figures

imqwerty:

you can make this figure from the given information (:

imqwerty:

it has 6 equilateral triangles, all having the same area because they have the same side length which is equal to the side length of the hexagon

RyeBread1:

what does it mean? Like from the options I have given you, which would you say fits best?

imqwerty:

do you know how to multiply?

RyeBread1:

yes

imqwerty:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @RyeBread1 A. 6(4a2 – 3) B. 6(8a2 – 9) C. 6a(12a – 9) D. 6a(18a – 12) Here they are \(\color{#0cbb34}{\text{End of Quote}}\) you could just multiply and expand the options to see which one matches with the given area of the hexagon, that'll be your answer

imqwerty:

not the best approach but it works in this case.

RyeBread1:

what am i multiplying

RyeBread1:

lol

imqwerty:

the things inside the parentheses with the things outside the parentheses... for example option B- \(6(8a^2 -9) = 6*8a^2 -9*6 \\~~~~~~~~~~~~~~~~~~~= 48a^2 - 54\)

RyeBread1:

ok so i just have to subtract 48a ^2 by 54?

imqwerty:

no lol

RyeBread1:

oh

imqwerty:

What do you get when you multiply and expand option A?

RyeBread1:

i dont know because i dont understand what expand means. i know i sound really dumb but i honestly have no idea how to do this

imqwerty:

aight i'll walk you through

imqwerty:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @imqwerty the things inside the parentheses with the things outside the parentheses... for example option B- \(6(8a^2 -9) = 6*8a^2 -9*6 \\~~~~~~~~~~~~~~~~~~~= 48a^2 - 54\) \(\color{#0cbb34}{\text{End of Quote}}\) do you understand how i opened the parantheses here?

RyeBread1:

thanks

RyeBread1:

yeah you used the distributive property

imqwerty:

yeah, that's what i mean when i say 'expand' so try using the distributive property on option A

RyeBread1:

ohh ok

imqwerty:

tell me what you get

RyeBread1:

ok

RyeBread1:

24a^2-3

RyeBread1:

is that right

imqwerty:

the first term (24a^2) is correct but not the second term (3)

RyeBread1:

what am i supposed to do to term 3

imqwerty:

|dw:1582393973778:dw|

imqwerty:

you didn't use the distributive property correctly. Check this image above and try using the distributive property again on option A

RyeBread1:

is it supposed to be 24a^2-18

imqwerty:

yes

RyeBread1:

haha im so smart i got it right and thats the right answer

RyeBread1:

Thanks so much!

imqwerty:

yw

imqwerty:

checking the options using distributive property worked in this case because of weak options imagine an option E) 2(12a^2 - 9) It gives the same result: 24a^2 -18 when you use the distributive property but it's not correct because the expression 2(12a^2 -9) is not based on the area of triangle

RyeBread1:

ohhh very true i get these type of ?s now!

imqwerty:

there are 6 triangles each having an equal area. So you could just multiply the area of one triangle with 6 to get the area of the hexagon. so your expression should be of type: \(6 \times (Area~of~one~triangle)\) it has to have a 6 and a quadrative term(the expression for the area of the triangle is a quadratic term) and the entire expression should also simplify to the area of the hexagon. The option follows this is correct.

RyeBread1:

thanks for the help because i wouldnt have gotten a good score if i hadnt posted that question. I got an 80% just so you know

imqwerty:

That's nice :) yw

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