how would you find the max of this:

400/(484t^2-1452t+1189)? and what t is at this max?

Question

how would you find the max of this:

400/(484t^2-1452t+1189)? and what t is at this max?

justjm · Answer

max would be infinity, right? If you evaluate the vertical asymptote at 1.5, $\lim_{t\rightarrow\ 1.5}=\infty$

darkknight · Answer

its 4, though

justjm · Answer

hold on I'm confuzzled

it's $\frac{400}{484x^{2}-1452x+1089}$  right

InsatiableSuffering · Answer

Are you allowed to use the calculator on this? You can simply plug it into y= and then use 2nd trace to find the maximum of the function.

darkknight · Answer

+1189 instead of 1089 but yes

darkknight · Answer

we can use only a scientific calculator and im in precalc not calc

darkknight · Answer

I don't know second trace

darkknight · Answer

no, just not graphing

darkknight · Answer

we can't use a graphing calculator

InsatiableSuffering · Answer

OH WAIT I think I know now

InsatiableSuffering · Answer

You need to use $$\frac{ -b }{ 2a  }$$ to find the vertex. This allows you topinpoint the ABSOLUTE MINIMUM value of the quadratic, as it opens upwards. Thus, you find your value of t that will satisfy the equation.

InsatiableSuffering · Answer

Then just plug in that value and solve for y

darkknight · Answer

oh lol, time to go back to algebra 1 :)